Answer:
Explanation:
a )
Depth of hole from surface of water d = .50 m - .03 m = .47 m
velocity of efflux v = √ 2gd
v = √ (2 x 9.8 x .47 )
v = 3.03 m /s
b )
Volume flow rate = π R² v where R is radius of hole at the bottom .
= 3.14 x ( .005 ) ² x 3.03 m/s
= 2.378 x 10⁻⁴ m³ /s
c )
Volume of water collected in 60 s
= 2.378 x 10⁻⁴ x 60
= 1.4268 x 10⁻² m³
If height attained in collecting container be h
π R² h = 1.4268 x 10⁻² m³ where R is radius of container
3.14 x ( .1 )² x h = 1.4268 x 10⁻²
h = .4544 m .
Pressure at the bottom of container = hρ g
where h is height of water , ρ is density of water
Pressure = .4544 x 1000 x 9.8 N /m²
= 4453.12 N /m²
The force on the box is:
F = mgsin∅
If we multiply by this with the distance it traveled, we will know the work done by the box.
W = dmgsin∅
This work will be converted to elastic potential energy in the spring which is:
1/2 kx². Equating these and substituting values:
1/2 * 170 * x² = 4 * 13 * 9.81 * sin(30)
x = 1.73 m
The box's maximum speed will at the point right before contact with the spring, when the compression is 0.
Answer: Electrons move from the potassium atoms to the sulfur atoms.
Explanation: 2 K + S ⇒ 2 K^+ + S^2- . Usually metals donor electrons to non-metals
Answer: 100 N
Explanation:
F = ma = 0.5(200) = 100 N