Ngan's mass on earth is 85kg.
Ngan has a weight on Mars = 14.5 N
Ngan’s weight on Earth = 833.0 N
Ngan’s mass on Earth = ?
<span>Fg,earth = mg(earth)</span>
<span>M = Fg,earth </span><span>/ g(earth)</span>
<span>M = 833.0 N / 9.8 m/s2</span>
<span>M = 85 kg</span>
During that period of time, the bird's displacement was 4 km east. So its velocity was (4km east)/(11hrs). That's 0.36 km/hour east. (rounded)
Answer:
d = 76.5 m
Explanation:
To find the distance at which the boats will be detected as two objects, we need to use the following equation:

<u>Where:</u>
θ: is the angle of resolution of a circular aperture
λ: is the wavelength
D: is the diameter of the antenna = 2.10 m
d: is the separation of the two boats = ?
L: is the distance of the two boats from the ship = 7.00 km = 7000 m
To find λ we can use the following equation:
<u>Where:</u>
c: is the speed of light = 3.00x10⁸ m/s
f: is the frequency = 16.0 GHz = 16.0x10⁹ Hz
Hence, the distance is:

Therefore, the boats could be at 76.5 m close together to be detected as two objects.
I hope it helps you!
D. The environment
Is the right answer
Answer:
x sin nx = x cos nx
same as
theta / theta x (xsin (nx)) = sin (nx) + (nx) cos (nx)