Evaluate the expression when x = 24 and p = -4.

Suppose the supply curve of portable radio rentals in Golden Gate Park is given by P = 5 + 0.1Q, where P is the daily rent per u

Tasya [4]

Answer:

10 or 1000 in hundreds of units

Step-by-step explanation:

Given the supply curve of portable radio rentals:

$P = 5 + 0.1Q$

and the demand curve for portable radio rentals:

$P = 20 - 0.2Q$

we need to find the equilibrium of these two curves ( replace either's right hand side on the other's left hand side)

we have:

$20 - 0.2Q = 5 + 0.1Q$

solving we have $Q=50$ or $5000$ in hundreds of units

Now the noise is equal to 3, therefore, we have to find the social supply curve by adding 3 to the first supply curve. following:

$P = 8 + 0.1Q$

We find the intersection bewteen the social supply curve and the demand curve ( social equilibrium rental ):

$20 - 0.2Q = 8 + 0.1Q$

Which gives $Q=40$ or $4000$ in hundreds of units.

Now that we integrated the noise into our considerations, the equilibrium rental exceeds the social equilibrium rental by 10 (50-40) (1000 in hundreds of units)

7 0

4 years ago

Below is a Venn Diagram.

PIT_PIT [208]

Answer:

A = 8, B = 9 and C = 6.

Step-by-step explanation:

We can create equations to solve this:

6 + A = 14

So A = 8.

A + B = 17

8 + B = 17

B = 9.

C = 29 - (6 + A + B)

= 29 - ( 6 + 8 + 9)

= 29 - 23

= 6.

6 0

3 years ago

Find the volume of the cone whose base is shown and whose altitude is 8 meters.

Aloiza [94]

$\bf \textit{volume of a cone}\\\\
V=\cfrac{\pi r^2 h}{3}\implies V=\stackrel{base~area}{\pi r^2}\cdot \cfrac{1}{3}\stackrel{height}{h}\\\\
-------------------------------\\\\
\textit{base of this cone}\\\\
B=\stackrel{a~square}{5\cdot 5}+\stackrel{semi-circle}{\frac{\pi r^2}{2}}\implies B=25+\frac{\pi 3^2}{2}\\\\\\ B=\stackrel{square}{25}+\stackrel{semi-circle}{\frac{9\pi }{2}}
\\\\\\
\textit{height of this cone is just 8}\\\\
-------------------------------\\\\$

$\bf \textit{volume of this cone}\\\\
V=B\cdot \cfrac{1}{3}h\implies V=\left( 25+\cfrac{9\pi }{2} \right)\left( \cfrac{8}{3} \right)
\\\\\\
V=\cfrac{200}{3}+\cfrac{3\pi\cdot 4 }{1}\implies V=\cfrac{200}{3}+12\pi$

7 0

4 years ago

I don’t understand 12 and 14

Lena [83]

#12:
p= 2.8y+2.2y+2x+5x+4x
p= 5y+11x

#14:
p= 2h+2h+4j+4j+4j+4j
p= 4h+16j

3 0

3 years ago

1. (You may get teacher help with this during tutoring)

Nezavi [6.7K]

Answer:

1A --- 25

1B --- (5 + 4) x 2 + 6 - 2 x 2 - 1 = 19

2A --- -206

2B --- ?

3A --- 5.8 × 10⁷

3B --- 2.5 × 10⁻³

4A --- 4.67 × 10¹³

4B --- 3.5 × 10⁻³

5A --- 9 × 10⁶

5B --- 1.68 × 10¹⁰

5C --- All ants combined weigh 112.46 times more than all humans combined

Step-by-step explanation:

(I am using PEMDAS for Order of Operations)

1A -----------------------------------------------

6 × 7 - 3² × 9 + 4³

Parenthesis

No parenthesis.

Exponents

6 × 7 - 3² × 9 + 4³

6 × 7 - 9 × 9 + 64

Multiplication

6 × 7 - 9 × 9 + 64

42 - 81 + 64

Division

No division.

Addition

42 - 81 + 64 (the 81 is negative)

42 + -17

25

1B --------------------------------------

5 + 4 x 2 + 6 - 2 x 2 - 1 = 14

(5 + 4) x 2 + 6 - 2 x 2 - 1 = 19

9 x 2 + 6 - 2 x 2 - 1

18 + 6 - 2 x 2 - 1

18 + 6 - 4 - 1

24 - 5

19

2A --------------------------------------------

3 × 7 - 3³ × 9 + 4²

Parenthesis

No parenthesis

Exponents

3 × 7 - 27 × 9 + 16

Multiplication

21 - 27 × 9 + 16

21 - 243 + 16

Addition

21 - 243 + 16

21 - 227

Subtraction

21 - 227

-206

2B ---------------------------------------------

5 + 3 × 2 + 6 - 2 × 3 - 7 = 4

(sorry cant figure this one out)

3A ------------------------------------------------

Move the decimal point in 58,000,000.0 over x times until you have 5.8000000. It was moved to the left 7 times, so the answer is 5.8 × 10⁷.

3B -----------------------------------------------

Move the decimal point in 0.0025 over x times until you have 2.5. It was moved to the right 3 times, so the answer is 2.5 × 10⁻³.

4A -----------------------------------------------

Move the decimal point in 46,700,000,000,000.0 x times until you have 4.67. It was moved to the left 13 times so the answer is 4.67 × 10¹³.

4B ----------------------------------------------

Move the decimal point in 0.0035 x times until you have 3.5. It was moved to the right 3 times, so the answer is 3.5 × 10⁻³.

5A -------------------------------------------------

(4.5 × 10³)(2 × 10³)

4.5 × 2 = 9

10³ × 10³ = 10⁶

9 × 10⁶

5B ------------------------------------------------------

(1.4 × 10⁵)(1.2 × 10⁵)

1.4 × 1.2 = 1.68

10⁵ * 10⁵ = 10¹⁰

1.68 × 10¹⁰

5C ---------------------------------------------------------

An adult human is 65 kilograms.

6.5 × 10¹ grams

An ant is (you didnt say how many so im going with) 5 grams.

5 × 10⁰ grams

6.84 billion humans

6,840,000,000.0 humans

6.84 × 10⁹ humans

10,000 trillion ants

1 × 10¹⁶ ants

Weight of humans:

(6.5 × 10¹)(6.84 × 10⁹)

44.46 × 10¹⁰

All humans weigh 4.446 × 10¹¹ kilograms

Weight of ants:

(5 × 10⁰)(1 × 10¹⁶)

All ants weigh 5 × 10¹⁶ grams

1000 grams per kilogram

1000 = 1 × 10³

5 × 10¹⁶ ÷ 1 × 10³

5 ÷ 1 = 5

16 - 3 = 13

All ants weigh 5 × 10¹³ kilograms

All humans weigh 4.446 × 10¹¹ kilograms

5 × 10¹³ ÷ 4.446 × 10¹¹ = 112.46

All ants combined weigh 112.46 times more than all humans combined

7 0

3 years ago