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3 years ago

How do you change slope intercept into standard form?

Mathematics

1 answer:

IrinaK [193]3 years ago

5 0

You change the slope intercept into standard form using the pathagoryum theory

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May I please receive help

mafiozo [28]

Hello mate ☺️,

We know that m < 2 = 96°, as,

$m < 5 = 96°$ (Alternate angles are equal)

Now we know that m < 5 = 96°, so,

$→ m < 5 + m < 8 = 180°$ (Linear Pair angles are supplementary)

$→ 96° + m < 8 = 180°$

$→ m < 8 = (180 - 96)°$

$→ m < 8 = 84°$

Therefore, m<5 = 96° & m<8=84°

✍️ By Benjemin ☺️

3 0

2 years ago

Please help I need this for a text ASAP.

Sladkaya [172]

The values of x and y are 45 and 8.

<h3>What is a Linear Pair of Angles?</h3>

When two lines meet at a single point, a pair of linear angles is created. If the angles follow the point where the two lines cross, they are considered to be linear. A linear pair's angles add up to 180° in every case.

Given:

Measures of two linear pairs of angles which are of equal measures are 2x and 11y + 2.

As the sum of linear pair of angles is 180°, and if they are of equal measures, each angle must be equal to 90°.

To determine the values of x and y we equate the given angles to 90°.

2x = 90°

⇒ x = 45

And 11y+2 = 90°

⇒ 11y = 90-2 = 88

⇒ y = 8

To know more about linear pairs visit:

brainly.com/question/17525542

#SPJ13

8 0

1 year ago

Please help

larisa [96]

Step-by-step explanation:

1/3,0,9

9,3,27

1/9,3,27

3 0

3 years ago

Graph the function. y=-x-6 ifx<-6 y = 2x + 12 if x>-6

Naddik [55]

Answer:

see attached

Step-by-step explanation:

For x < -6, the function has a slope of -1 and an x-intercept of -6.

For x > -6, the function has a slope of 2 and an x-intercept of -6.

The function given here is not defined at x=6, so there is a hole at (-6, 0).

7 0

3 years ago

Evaluate the function at the indicated values. f(x)= 6x^2+ 5x -12

seropon [69]

Step-by-step explanation:

We need to find the value of the function at the indicated value.

$f(x)= 6x^2+ 5x -12$

Indicated values are : f(-7), f(0), f(6), f(7)

To find f(-7), put x = -7 in the given function

$f(-7)= 6(-7)^2+ 5(-7) -12=247$

To find f(0), put x = 0 in the given function

$f(0)= 6(0)^2+ 5(0) -12=-12$

To find f(6), put x = 6 in the given function

$f(6)= 6(6)^2+ 5(6) -12=234$

To find f(7), put x = 7 in the given function

$f(7)= 6(7)^2+ 5(7) -12=317$

Hence, this is the required solution.

8 0

3 years ago