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WINSTONCH [101]
3 years ago
8

A car covered a certain distance at a speed of 24 mph. While returning, the car covered the same distance at a speed of 16 mph.

What was the average speed of the car for the entire journey?
Mathematics
2 answers:
igomit [66]3 years ago
7 0
Since the distances were the same you can find the average speed directly by adding the speeds then dividing by 2. No need to weight anything.

If we’re considering speed regardless of direction, the average speed is:

(24 + 16) / 2 = 40 / 2 = 20mph

However if direction matters, then one number has to be negative since the directions are opposite:

(24 - 16) / 2 = 8 / 2 = 4mph (in the positive direction)

Depending on the context, either of these could be your answer.
AlekseyPX3 years ago
3 0

Answer:

19.2

Step-by-step explanation:

do it yourself

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Use the following diagram to find the angle measures of the triangle, rounded to the nearest degree.
nadezda [96]

Answer:

m∠A = 30°

m∠B = 80°

m∠C = 70°

Step-by-step explanation:

By applying cosine rule in the given triangle,

b² = a² + c² - 2ac[cos(∠B)]

From the given triangle,

a = 14 m

b = 28 m

c = 24 m

(28)² = (14)² + (24)² - 2(14)(24)cos(B)

784 = 196 + 576 - 672cos(∠B)

cos(∠B) = 0.1786

∠B = \text{cos}^{-1}(0.1786)

∠B = 79.71°

∠B = 80°

By applying sine rule in the given triangle,

\frac{\text{sinA}}{a}= \frac{\text{sinB}}{b}= \frac{\text{sinC}}{c}

\frac{\text{sinA}}{14}= \frac{\text{sin(79.71)}}{28}= \frac{\text{sinC}}{24}

\frac{\text{sinA}}{14}= \frac{\text{sin(79.71)}}{28}

\text{sinA}= \frac{\text{sin(79.71)}\times 14}{28}

sinA = 0.491958

A = 29.47°

A ≈ 30°

By applying triangle sum theorem,

m∠A + m∠B + m∠C = 180°

30° + 80° + m∠C = 180°

m∠C = 70°

4 0
3 years ago
Look below at the image provided.
vesna_86 [32]

That would be angle 2. It is on the opposite of angle 7 and it is inside the two parallel lines

Hope this helped!

~Just a girl in love with Shawn Mendes

5 0
3 years ago
3 6/4 in simplest form
ivanzaharov [21]

Answer:

4 1/2.

hope this helps!

6 0
2 years ago
Solve for (f+g)(5) if f(x)=6x+3 and g(x)=x-4 show you work please
Diano4ka-milaya [45]
There are two ways to do this.

The first way is to algebraically find (f+g)(x) first and plug in x = 5 later. Doing that method leads us to
(f+g)(x) = f(x) + g(x)
(f+g)(x) = 6x+3 + x-4
(f+g)(x) = 7x-1
(f+g)(5) = 7(5)-1
(f+g)(5) = 34

OR

you can compute f(5) and g(5) first, then add up those sub-results to get
f(x) = 6x+3
f(5) = 6(5)+3
f(5) = 33
g(x) = x-4
g(5) = 5-4
g(5) = 1
Adding up these results gives: (f+g)(5) = f(5) + g(5) = 33+1 = 34

Either way, the final answer is 34

7 0
3 years ago
The graph below shows the solution to which system of inequalities? ​
solong [7]

Answer:

C

Step-by-step explanation:

The graph shows it clearly.

6 0
2 years ago
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