In this problem, an angle like angle BAC where the
vertices like on the circle itself is called the inscribed angle.
While angle BOC, where O is the center of the circle, is
called the central angle.
Using Proposition III.20 from Euclid's Elements, this is called
the Inscribed Angle Theorem wherein:
∠BOC = 2∠BAC
or ∠BOC / 2 = ∠<span>BAC</span>
<h3>
Answer: MH = 7</h3>
=====================================================
Explanation:
The double tickmarks for quadrilateral MATH show that MA = TH. Since TH is 5 units long, this makes MA the same length as well.
For quadrilateral ROKS, we have RO = 15. For "MATH" and "ROKS" we have "MA" and "RO" as the first two letters of each four-letter sequence; meaning that MA and RO correspond together.
The ratio of the corresponding segments is RO/MA = 15/5 = 3.
The larger quadrilateral has each side length 3 times longer than the smaller quadrilateral's corresponding side lengths.
--------------
In short,
larger side = 3*(smaller side)
--------------
Using this scale factor of 3, we can find MH
larger side = 3*(smaller side)
RS = 3*(MH)
21 = 3*MH
3*MH = 21
MH = 21/3
MH = 7
(x, y) = ( cos 45, sin 45) =
![=\text{ (}\frac{\sqrt[]{2}}{2}\text{ , }\frac{\sqrt[]{2}}{2}\text{ )}](https://tex.z-dn.net/?f=%3D%5Ctext%7B%20%28%7D%5Cfrac%7B%5Csqrt%5B%5D%7B2%7D%7D%7B2%7D%5Ctext%7B%20%2C%20%7D%5Cfrac%7B%5Csqrt%5B%5D%7B2%7D%7D%7B2%7D%5Ctext%7B%20%29%7D)
The correct option is A
