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2 years ago

Hakim recorded his finishing time, in seconds, for each time he ran the 100 m race during one track season.

Mathematics

1 answer:

Alchen [17]2 years ago

7 0

Its 12.1. it is the middle number from largest to least value.

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What weather condition does the map indicate?

Temka [501]

Answer: C) an occluded front leading to a tropical storm

Step-by-step explanation: it is occluded because the two cool and warm fronts are joined together creating a tropical storm.

3 0

3 years ago

Evaluate the integral Integral ∫ from (1,2,3 ) to (5, 7,-2 ) y dx + x dy + 4 dz by finding parametric equations for the line seg

n200080 [17]

$\vec F(x,y,z)=y\,\vec\imath+x\,\vec\jmath+3\,\vec k$

is conservative if there is a scalar function $f(x,y,z)$ such that $\nabla f=\vec F$ . This would require

$\dfrac{\partial f}{\partial x}=y$

$\dfrac{\partial f}{\partial y}=x$

$\dfrac{\partial f}{\partial z}=3$

(or perhaps the last partial derivative should be 4 to match up with the integral?)

From these equations we find

$f(x,y,z)=xy+g(y,z)$

$\dfrac{\partial f}{\partial y}=x=x+\dfrac{\partial g}{\partial y}\implies\dfrac{\partial g}{\partial y}=0\implies g(y,z)=h(z)$

$f(x,y,z)=xy+h(z)$

$\dfrac{\partial f}{\partial z}=3=\dfrac{\mathrm dh}{\mathrm dz}\implies h(z)=3z+C$

$f(x,y,z)=xy+3z+C$

so $\vec F$ is indeed conservative, and the gradient theorem (a.k.a. fundamental theorem of calculus for line integrals) applies. The value of the line integral depends only the endpoints:

$\displaystyle\int_{(1,2,3)}^{(5,7,-2)}y\,\mathrm dx+x\,\mathrm dy+3\,\mathrm dz=\int_{(1,2,3)}^{(5,7,-2)}\nabla f(x,y,z)\cdot\mathrm d\vec r$

$=f(5,7,-2)-f(1,2,3)=\boxed{18}$

8 0

3 years ago

Distribute the expression.<br> 5(282-38+4)

kifflom [539]

Answer:

10s²-15s+20 is yr answer..

Step-by-step explanation:

5(2s²-3s+4)
10s²-15s+20

<h3>stay safe healthy and happy.</h3>

6 0

2 years ago

What is the range of the function f(x) = |x| + 5?

Ierofanga [76]

Answer:

$[0, \infty)$

5 0

1 year ago

Read 2 more answers

An airplane flying at attitude of 32,000 feet descends at a rate of 1,300 feet per minute. If the plane descends for 15 minutes,

Furkat [3]

Since the plane descends 1,300 feet per minute it would descend 19,500 feet after 15 minutes (1,300 x 15 = 19,500) Subtract this from the plane's initial altitude 32,000 and the new altitude will be 12,500. (32,000-19,500=12,500)

6 0

3 years ago