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Nezavi [6.7K]
3 years ago
6

If the sales tax rate is 7.25% in California, then how much would you pay in Los Angeles for a coat that cost $120.00?

Mathematics
2 answers:
meriva3 years ago
5 0
214.50 is the final price on how much they will pay
AfilCa [17]3 years ago
5 0

Answer:

If the sales tax rate is 7.25% in California, I would pay $128.70 for a coat that costs $120.00.

Step-by-step explanation:

If the sales tax rate is 7.25%, and the coat costs $120.00, to know the final price of the product we have to calculate the tax amount and add it to the original price.

-SALES TAX RATE: 120 / 100 x 7.25 = 8.7

-FINAL PRICE: 120 + 8.7 = $128.70

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7 pounds for $10.43; 10 pounds for a dollars
olya-2409 [2.1K]

Answer:

7pounds=$10.43

10 pounds=? solution 10.43×10÷7=14.9 the equals sign means cross multiply.

8 0
3 years ago
Solve for x. 2x - 9 I - 2 16<br>i need how yo solve <br>​
puteri [66]
Can you rewrite the equation? It doesn’t make sense
4 0
3 years ago
The line L is a tangent to the curve with equation y= 4x^2 +1 . The line L cuts the y axis at (0,8) and has a positive gradient.
sergeinik [125]

A generic point on the graph of the curve has coordinates

(x, 4x^2+1)

The derivative gives us the slope of the tangent line at a given point:

f(x) = 4x^2+1 \implies f'(x) = 8x

Let k be a generic x-coordinate. The tangent line to the curve at this point will pass through (k, 4k^2+1) and have slope 8k

So, we can write its equation using the point-slope formula: a line with slope m passing through (x_0, y_0) has equation

y-y_0 = m(x-x_0)

In this case, (x_0, y_0)=(k, 4k^2+1) and m=8k, so the equation becomes

y-4k^2-1 = 8k(x-k)

We can rewrite the equation as follows:

y-4k^2-1 = 8k(x-k) \iff y = 8kx - 8k^2+4k^2+1 \iff y = 8kx-4k^2+1

We know that this function must give 0 when evaluated at x=0:

f(x) = 8kx-4k^2+1 \implies f(0) = -4k^2+1 = 8 \iff -4k^2 = 7 \iff k^2 = -\dfrac{7}{4}

This equation has no real solution, so the problem looks impossible.

5 0
3 years ago
A major department store chain is interested in estimating the mean amount its credit card customers spent on their first visit
sergiy2304 [10]

Answer:

95% Confidence interval: (39.43, 61.58)

Step-by-step explanation:

We are given the following in the question:

Sample mean, \bar{x} = $50.50

Sample size, n = 15

Alpha, α = 0.05

Sample standard deviation = 20

95% Confidence interval:

\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}  

Putting the values, we get,  

t_{critical}\text{ at degree of freedom 14 and}~\alpha_{0.05} = \pm 2.1447  

=50.50 \pm 2.1447(\dfrac{20}{\sqrt{15}} ) \\\\= 50.50 \pm 11.0751 \\= (39.4249,61.5751)\\\approx (39.43, 61.58)  

95% Confidence interval: (39.43, 61.58)

8 0
3 years ago
Write an equation in slope-intercept form for the line parallel to y=3x-2 that passes through the point (5,-2)
Aneli [31]

Answer:

y = 3x - 17

Step-by-step explanation:

Parallel lines have the same slope.

The slope of the given line, y = 3x - 2 is 3.

The equation we are looking for is of the form

y = mx + b

Since we know the slope, m, is 3, we have

y = 3x + b

To find the value of b, we substitute x and y with the values from the given point and solve for b.

-2 = 3(5) + b

b = -17

The equation is

y = 3x - 17

6 0
3 years ago
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