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Trava [24]
2 years ago
12

What times what is -10 but when added is -3

Mathematics
2 answers:
erastova [34]2 years ago
7 0

Answer:

-5 times 2 is -10

-5+2=-3

Thus the answer is -5 and 2

Step-by-step explanation:

Hope this helps!

nlexa [21]2 years ago
3 0
Njevvefwbfwbdbx crisis
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In the figure the horizontal lines are parallel and ab=bc=cd if lm =5 find jm
lisabon 2012 [21]
By the transversal theorem, if segments on a transversal cut by parallel lines are equal, then similar segments cut by the same parallel lines on another transversal are also equal.
Therefore
JK=KL=LM=5
=>
JM=3*5=15
8 0
3 years ago
I’m stuck on this question. Help please
mote1985 [20]

Answer:

Salt: 1, 2, 4

Pepper: 1/2, 1, 2

Garlic Powder: 1/4, 1/2, 1

Onion Powder: 1/4, 1/2, 1

Step-by-step explanation:

The batches are doubling each time.

6 0
2 years ago
A researcher was interested in comparing the resting pulse rates of people who exercise regularly and people who do not exercise
DiKsa [7]

Answer:

We Reject H₀ if t calculated > t tabulated

But in this case,

0.83 is not greater than 2.056

Therefore, we failed to reject H₀

There is no difference between the mean pulse rate of people who do not exercise and the mean pulse rate of people who do exercise.

Step-by-step explanation:

Refer to the attached data.

The Null and Alternate hypothesis is given by

Null hypotheses = H₀: μ₁ = μ₂

Alternate hypotheses = H₁: μ₁ ≠ μ₂

The test statistic is given by

$ t = \frac{\bar{x}_1  - \bar{x}_2}{\sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} } }  $

Where \bar{x}_1 is the sample mean of people who do not exercise regularly.

Where \bar{x}_2 is the sample mean of people who do exercise regularly.

Where s_1 is the sample standard deviation of people who do not exercise regularly.

Where s_2 is the sample standard deviation of people who do exercise regularly.

Where n_1 is the sample size of people who do not exercise regularly.

Where n_2 is the sample size of people who do exercise regularly.

$ t = \frac{72.7  - 69.7}{\sqrt{\frac{10.9^2}{16} + \frac{8.2^2}{12} } }  $

t = 0.83

The given level of significance is

1 - 0.95 = 0.05

The degree of freedom is

df = 16 + 12 - 2 = 26

From the t-table, df = 26 and significance level 0.05,

t = 2.056 (two-tailed)

Conclusion:

We Reject H₀ if t calculated > t tabulated

But in this case,

0.83 is not greater than 2.056

Therefore, We failed to reject H₀

There is no difference between the mean pulse rate of people who do not exercise and the mean pulse rate of people who do exercise.

4 0
3 years ago
On Monday, Takira counted 75 splatters of bird droppings on her car. On Tuesday afternoon, she counted 21 more. What is the perc
Law Incorporation [45]

Answer:

28%

Step-by-step explanation:

percent change in the number of bird droppings = increase in splatters / splatters counted on Monday x 100

\frac{21}{75} x 100 = 28%

3 0
2 years ago
Sandy charges each family that she babysits for a flat fee of $10 for the night and $5 extra per
Pani-rosa [81]
30 = 5x + 10 so x = 4
5 0
3 years ago
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