Determine if the scenario is independent or dependent:

Mathematics

1 answer:

Lady_Fox [76]3 years ago

6 0

Answer:

dependent

Step-by-step explanation:

A scenario is called independent if the outcome of one event will not influence the outcome of the other. We are trying to assign a position for each player so that everyone gets a position. But we also need to make no one can have more than one position.

Let's say we have position X, Y, Z for player A, B, C. First you assign the position for player A, there will be 3 possible positions (A/B/C). If you assign position X to player A, player B can't get the X position so the possible outcome is only two(B or C). This makes the scenario dependent because the outcome of the first roll will influence the possible outcome of the next roll.

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sergij07 [2.7K]

$f(t)=\begin{cases}0&\text{for }t$

Recall that

$u(t)=\begin{cases}0&\text{for }t$

Take it one piece at a time. For $t\ge0$ , we can scale $u(t)$ by -5:

$-5u(t)=\begin{cases}0&\text{for }t$

If we shift the argument by 1 and scale by -5, we have

$-5u(t-1)=\begin{cases}0&\text{for }t$

so if we subtract this from $-5u(t)$ , we'll end up with

$-5u(t)+5u(t-1)=\begin{cases}0&\text{for }t$

For the next piece, we can add another scaled and shifted step like

$-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t$

so that

$-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)=\begin{cases}0&\text{for }t$

For the last piece, we add one more term:

$6u(t-7)=\begin{cases}0&\text{for }t$

and so putting everything together, we get $f(t)$ :

$f(t)\equiv-5u(t)+5u(t-1)-6u(t-1)+6u(t-7)+6u(t-7)$
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Answer:

Step-by-step explanation: