Let distance form the pole = x and height of the hill = y ft
now we can set up 2 equayions
tan 18 = (40-y)/x
tan 14 = y/x
from second equation y = sxtan14 so we have:-
tan 18 = ( 40 - x tan 14) / x
x tan 18 = 40 - x tan 14
x(tan 18 + tan 14) = 40
x = 40 / (tan18 + tan 14) = 69.66 feet Answer
Answer:
ummm where is the question anyway?
Since sin(2x)=2sinxcosx, we can plug that in to get sin(4x)=2sin(2x)cos(2x)=2*2sinxcosxcos(2x)=4sinxcosxcos(2x). Since cos(2x) = cos^2x-sin^2x, we plug that in. In addition, cos4x=cos^2(2x)-sin^2(2x). Next, since cos^2x=(1+cos(2x))/2 and sin^2x= (1-cos(2x))/2, we plug those in to end up with 4sinxcosxcos(2x)-((1+cos(2x))/2-(1-cos(2x))/2)
=4sinxcosxcos(2x)-(2cos(2x)/2)=4sinxcosxcos(2x)-cos(2x)
=cos(2x)*(4sinxcosx-1). Since sinxcosx=sin(2x), we plug that back in to end up with cos(2x)*(4sin(2x)-1)
Answer:
D. 10x - 5
General Formulas and Concepts:
<u>Algebra I</u>
- Terms/Coefficients/Degrees
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = 2x + 5x
g(x) = 3x - 5
(f + g)(x) is f(x) + g(x)
<u>Step 2: Simplify</u>
f(x) = 7x
g(x) = 3x - 5
<u>Step 3: Find</u>
- Substitute: (f + g)(x) = 7x + (3x - 5)
- Combine like terms: (f + g)(x) = 10x - 5
