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iogann1982 [59]
3 years ago
12

4.

Mathematics
1 answer:
kow [346]3 years ago
5 0

Answer:

B

Step-by-step explanation:

The equation of a circle in standard form is

(x - h)² + (y - k)² = r²

where (h, k) are the coordinates of the centre and r is the radius

(x + 7)² + (y - 5)² = 16 ← is in standard form

with centre = (- 7, 5 ) and r = \sqrt{16} = 4 → B

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3 years ago
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Please answer quickly<br>expand and simplify: 4(5x-3y) (x-4y) -(3x-4y)(2x+3y)​
Gekata [30.6K]

Answer: 14x^2-93xy+60y^2 Hope that helps!

Step-by-step explanation:

1. Expand by distributing terms

(20x-12y)(x-4y)-(3x-4y)(2x+3y)

2. Use the Foil method:(a+b)(c+d)= ac+ad+bc+bd

20x^2-80xy-12yx+48y^2-(3x-4y)(2x+3y)

3. Use the Foil method : (a+b)(c+d)= ac+ad+bc+bd

20x^2-80xy-12yx+48y^2-(6x^2+9xy-8yx-12y^2)

4. Remove parentheses 20x^2-80xy-12yx+48y^2-6x^2-9xy+ 8yx+12y^2

5. Collect like terms (20x^2-6x^2)+(-80xy-12xy-9xy+8xy)+(48y^2+12y^2)

6. Simplify.

And your answer would be 14x^2-93xy+60y^2

5 0
3 years ago
When a force of 30 N acts on a certain object the acceleration of the object is 5m/s2 if the force is changed to 54 N what will
PtichkaEL [24]

Answer:

The correct answer is 9 m per second^{2}

Step-by-step explanation:

Force is defined by mass of an object times it's acceleration.

Let the mass of the object be m kilograms.

When a force of 30 N acts on a certain object the acceleration of the object is 5 m per second^{2}

∴ 30 = m × 5

⇒ m = 6.

If the force is changed to 54 N, let the acceleration of the object be x  m per second^{2}.

∴ 54 = m × x

⇒ x = \frac{54}{6} = 9

Thus when the force is 54 N, the acceleration of the object is 9 m per second^{2}.

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agasfer [191]
Me don’t understand it i need more info
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Find the perimeter of the figure to the nearest hundredth. due today
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*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

Answer: 36.57

Explanation:

6x4 = 24

3.14(2)^2 = 12.56

12.57+24=36.57

I hope this helped!

<!> Brainliest is appreciated! <!>

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