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devlian [24]
3 years ago
14

I need help it will be great if you help me. :)

Mathematics
1 answer:
kvv77 [185]3 years ago
5 0
Divide everything by 8: 550/8=68.75, 250/8=31.25. The new dimensions are 68.75 inches by 31.25 inches :)
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Zigmanuir [339]

Answer:

Angle A = 19

Step-by-step explanation:

Vertical angles are congruent ( equal to each other )

If angle A and angle B are vertical angles and vertical angles are congruent then angle A = angle B

If angle A = 3x + 13 and angle B = 5x + 9 then 3x + 13 = 5x + 9

( Note that we just created an equation that we can use to solve for x )

We now solve for x using the equation created

3x + 13 = 5x + 9

Step 1 subtract 3x from both sides

Outcome: 13 = 2x + 9

Step 2 subtract 9 from both sides

Outcome: 4 = 2x

Step 3 divide both sides by 2

Outcome: x = 2

Now to find Angle A

All we have to do to find the measure of angle a is simply substitute 2 for x in it's given expression ( 3x + 13 )

Substitute 2 for x

Angle A = 3(2) + 13

Multiply

Angle A = 6 + 13

Add

Angle a = 19

3 0
3 years ago
Subtract 17 M -35 from 26M +18
kodGreya [7K]

Answer:

9m−17, if you mean 26m+18-17m-35

8 0
3 years ago
Your company is considering submitting a bid on a major project. You determine that the expected completion time is 130 weeks an
Olenka [21]

Answer:

Option C) 146.5

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 130 weeks

Standard Deviation, σ = 10 weeks

We are given that the distribution of completion time is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(X<x) = 0.95

We have to find the value of x such that the probability is 0.95

P(X < x)  

P( X < x) = P( z < \displaystyle\frac{x - 130}{10})=0.95  

Calculation the value from standard normal z table, we have,  

P(z

\displaystyle\frac{x - 130}{10} = 1.645\\x = 146.45 \approx 146.5  

The project should be completed in 146.5 weeks or less.

Hence, 146.5 weeks should be set the due date such that there is a 95 percent chance that the project will be finished by this time.

7 0
3 years ago
How do I solve the system of equations
Neporo4naja [7]
You will solve it simultaneously
4 0
4 years ago
If a logo of 6 ft and he needs a quart of paint for every 22 square ft how many quarte will he need for the whole logo
bulgar [2K]

Complete Question

If a logo has dimensions of 6 ft and 11ft, he needs a quart of paint for every 22 square ft. How many quarts will he need for the whole logo?

Answer:

3 quarts of paint

Step-by-step explanation:

The Logo is rectangular in shape, hence:

The area of a rectangle = Length × Width

The logo has dimensions of 6 ft and 11ft.

Area of the Logo = 6ft × 11ft = 66ft²

He needs a quart of paint for every 22 square ft

Hence:

22 ft² = 1 quart of paint

66ft² = x

Cross Multiply

22 ft² × x = 66 ft² × 1 quart

x = 66 ft² × 1 quart/22 ft²

x = 3 quarts of paint

Therefore, he will need 3 quarts of paint for the whole logo.

7 0
3 years ago
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