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4 years ago

HELP PLZ I AM STUCK!!!!!!!

Mathematics

2 answers:

shutvik [7]4 years ago

6 0

The answer is letter B. line l

raketka [301]4 years ago

3 0

So -2 is the domain so it is 2 left.

Then -3 is the range so you go 3 down.

so line M is the answer

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The graph shown is the solution set for which of the following inequalities?

elena55 [62]

The inequality is y < l x+3 l

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3 years ago

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SOLVE THE EQUATION!!!!!!!!

ololo11 [35]

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3 years ago

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If outliers are discarded, then the retirement savings by residents of Econistan is normally distributed with a mean of $100,000

zavuch27 [327]

Answer:

$P(X>117000)=P(\frac{X-\mu}{\sigma}>\frac{117000-\mu}{\sigma})=P(Z>\frac{117000-100000}{20000})=P(z>0.85)$

And we can find this probability using the complement rule and the normal standard table or excel:

$P(z>0.85)=1-P(z$

The firgure attached illustrate the problem

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the retirement savings of a population, and for this case we know the distribution for X is given by:

$X \sim N(100000,20000)$

Where $\mu=100000$ and $\sigma=20000$

We are interested on this probability

$P(X>117000)$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$P(X>117000)=P(\frac{X-\mu}{\sigma}>\frac{117000-\mu}{\sigma})=P(Z>\frac{117000-100000}{20000})=P(z>0.85)$

And we can find this probability using the complement rule and the normal standard table or excel:

$P(z>0.85)=1-P(z$

The firgure attached illustrate the problem

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3 years ago

What is the asymptote of g(x)= 4 (1/3) - 2

Nataly [62]

Answer: X=2

Step-by-step explanation:

Assuming the function is

All logarithmic functions, despite their base, has a vertical asymptote at argument = 0.

That is not changed by the vertical stretching made by the 4 which multiplies the logarithm nor the vertical shift made by the +5.

In this case the argument is x - 2, then the vertical asymptote is:

x - 2 = 0

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3 years ago

Consider the series 4 + 12 + 36 ... Find the sum of the first 9 terms.

jeyben [28]

Answer:

39364

Step-by-step explanation:

You can simplify the equation to make 4(1+3+9...) The nth term is therefore $3^{n-1}$ so u can substitute that into the equation so 4( $3^{n-1}+ 3^{n} + 3^{n+1}$ ..). This would simplify to 4( $3^0 +3+3^2$ + $3^3+3^4+3^5+3^6+3^7+3^8$ ). By simplifying this, you can make it so 4( $2^2+6^2+18^2+42^2+81^2$ ) = 4(4+36+324+2916+6561) =39364

3 0

2 years ago