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Ostrovityanka [42]
3 years ago
5

3/4 + (1/3 ÷ 1/6) - (-1/2) =?​

Mathematics
1 answer:
stepladder [879]3 years ago
8 0

Answer:

[See Below]

Step-by-step explanation:

✦ Turn fractions into decimals:

  • \frac{3}{4} =0.75  
  • -\frac{1}{2} =-0.5
  • (We will do something different for \frac{1}{3} and \frac{1}{6}.)

✦ Divide:

  • \frac{1}{3} ÷ \frac{1}{6}=2
  • (Since the denominators are multiplies of each other we can divide them without having to change them into decimals.)

✦ Simplified Equation:

  • 0.75+2-(-0.5)

✦ Add:

  • 0.75+2=2.75

✦ Subtract:

  • 2.75-(-0.5)=3.25
  • (Subtraction rule is if there is 2 negatives next to each other in a problem it turns into a positive.)

✦ So your answer would be:

  • \frac{13}{4} (Exact Form)
  • 3~ \frac{1}{4} (Mixed Number Form)
  • 3.25 (Decimal Form)

~<em>Hope this helps Mate. If you need anything feel free to message me. </em>

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Answer:

solution is

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Step-by-step explanation:

we are given

|10x+20|\leq 10

Firstly, we will find critical values

so, let's assume it is equal

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now, we can break absolute sign

For |10x+20|= -(10x+20):

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we can solve for x

-10x-20= 10

Add both sides by 20

-10x-20+20= 10+20

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Divide both sides by -10

and we get

x=-3

For |10x+20|= (10x+20):

(10x+20)= 10

we can solve for x

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Divide both sides by 10

and we get

x=-1

so, critical values are

x=-3

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now, we can draw a number line and locate these values

and then we can check inequality on each intervals

For (-\infty,-3):

We can select any random value from this interval and plug that in inequality

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we can plug x=-5

|10\times -5+20|\leq 10

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so, this is FALSE

For [-3,-1]:

We can select any random value from this interval and plug that in inequality

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|10\times -2+20|\leq 10

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so, this is TRUE

For (-1,\infty):

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=0

|10\times 0+20|\leq 10

|0+20|\leq 10

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so, this is FALSE

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[-3,-1]

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Step-by-step explanation:

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