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Ostrovityanka [42]
3 years ago
5

3/4 + (1/3 ÷ 1/6) - (-1/2) =?​

Mathematics
1 answer:
stepladder [879]3 years ago
8 0

Answer:

[See Below]

Step-by-step explanation:

✦ Turn fractions into decimals:

  • \frac{3}{4} =0.75  
  • -\frac{1}{2} =-0.5
  • (We will do something different for \frac{1}{3} and \frac{1}{6}.)

✦ Divide:

  • \frac{1}{3} ÷ \frac{1}{6}=2
  • (Since the denominators are multiplies of each other we can divide them without having to change them into decimals.)

✦ Simplified Equation:

  • 0.75+2-(-0.5)

✦ Add:

  • 0.75+2=2.75

✦ Subtract:

  • 2.75-(-0.5)=3.25
  • (Subtraction rule is if there is 2 negatives next to each other in a problem it turns into a positive.)

✦ So your answer would be:

  • \frac{13}{4} (Exact Form)
  • 3~ \frac{1}{4} (Mixed Number Form)
  • 3.25 (Decimal Form)

~<em>Hope this helps Mate. If you need anything feel free to message me. </em>

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Answer:

C. A square is a rhombus

Step-by-step explanation:

A square fulfills all the requirements to become a rhombus:

A. All sides being equal.

B. The diagonals bisected at an angle of 90 degrees

7 0
3 years ago
Part of the roof of a factory is devoted to mechanical support and part to green space. The area G that is designated as green s
alexgriva [62]

Answer:

Therefore, the area of green space would be 30 square yards.

Step-by-step explanation:

The area G that is designated as green space can be modeled by the polynomial 2x^2-7x

the area M that is devoted to mechanical support can be modeled by the polynomial x^2-9x+24.

We are asked to find the area of the green space, when area of roof (R) is 36 square yards.

The area of roof would be equal to sum of areas of green space and mechanical support.

R=G+M

G = 2x^2 -7x M = x^2 -9x +24

the total area is given by 36 yd^2. And we know that:

R = 36 yd^2 = G+M

Replacing the info given we got:

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And we can rewrite this expression like this:

3x^2 -16 x -12 =0

And we can use the quadratic formual to solve this problem:

X =\frac{-b \pm \sqrt{b^2 -4ac}}{2a}

With a = 3, b = -16 , c =-12. Replacing we have

x = \frac{16 \pm \sqrt{(-16)^2 -4*(3)*(-12)}}{2*3}

And the solutions for this case are:

Since length cannot be negative, therefore, the value of x would be 6.

The area of green space would be:

x = 6

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3 years ago
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CaHeK987 [17]
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3 years ago
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Answer:

No, it is incorrect.

Step-by-step explanation:

The quadratic equation is

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8 0
3 years ago
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Expression 3, 
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