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dimulka [17.4K]
3 years ago
14

Please answer quick!

Mathematics
1 answer:
elena-s [515]3 years ago
6 0

Answer:

84

Step-by-step explanation:

3 times 4= 12

12 times 7= 84

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Which equation represents a circle whose center is located at (- 6, 2) and whose radius is sqrt(10) units?
azamat

Answer:

{(x  + 6)}^{2}  +  {(y - 2)}^{2}=10

Step-by-step explanation:

The equation of a circle with center (a,b) and radius r, is

{(x - a)}^{2}  +  {(y - b)}^{2}  =  {r}^{2}

From the question, the center of the circle is located at (-6,2) and the radius is

r =  \sqrt{10}

We substitute the center and radius to get:

{(x -  - 6)}^{2}  +  {(y - 2)}^{2}  =  {( \sqrt{10} })^{2}

Simplify to obtain:

{(x  + 6)}^{2}  +  {(y - 2)}^{2}=10

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Answer:

Step-by-step explanation:

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