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2 years ago

14

You go to order ice cream sundae and there are lots of options! Each sundae includes one flavor of ice cream and one topping .Th

ere is strawberry, vanilla, and chocolate ice cream. You also get the choice of a topping. There are sprinkles, hot fudge, whipped cream or cookie crumbs. If you were to chose a sundae at random, find each probability.
1) P(Chocolate, sprinkles)

2) P( Vanilla, hot fudge)

3) P( Strawberry, cookie crumbs)

1 answer:

Naddik [55]2 years ago

4 0

Answer:

2.) P(Chocolate, sprinkles)

Step-by-step explanation:

A lot of people choose chocolate ice cream over other flavors, and a lot of people also like sprinkles on their ice cream.

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*^%Brainliest 15 pounds Question 5 (2 points)

galben [10]

Answer:

0

Step-by-step explanation:

Separate into two parts

$\frac{4xy^{3} }{2xy^{2} } + \frac{8x^{2} {y}^{5} }{2x {y}^{2} }$

Simplify:

This is for the first fraction

$\frac{4x {y}^{3} }{2x {y}^{2} } = (4 \div 2)(x \div x)( {y}^{3} \div {y}^{2} )$

$2(1)( {y}^{3 - 2} )$

$2{y}$

Now for the second fraction:

$\frac{8 {x}^{2} {y}^{3} }{2x {y}^{2} } = ( 8 \div 2)( {x}^{2} \div x)( {y}^{5} \div {y}^{2} )$

$4( {x}^{2 - 1} )( {y}^{5 - 2} )$

$4x {y}^{3}$

Add both parts together

$2y + 4x {y}^{3}$

To turn this into the said formula, that would become:

$2 {x}^{0} {y}^{1} + 4 {x}^{1} {y}^{3}$

Where:

a=0

b=1

c=1

d=3

Any value with an exponent 0 except zero will be equal to 1

4 0

3 years ago

Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated

Illusion [34]

Answer:

$x=-2,0,3$

Step-by-step explanation:

We have been given a function $f(x)=15x^3-15x^2-90x$ . We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

$15x^3-15x^2-90x=0$

Now, we will factor our equation. We can see that all terms of our equation a common factor that is $15x$ .

Upon factoring out $15x$ , we will get:

$15x(x^2-x-6)=0$

Now, we will split the middle term of our equation into parts, whose sum is $-1$ and whose product is $-6$ . We know such two numbers are $-3\text{ and }2$ .

$15x(x^2-3x+2x-6)=0$

$15x((x^2-3x)+(2x-6))=0$

$15x(x(x-3)+2(x-3))=0$

$15x(x-3)(x+2)=0$

Now, we will use zero product property to find the zeros of our given function.

$15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0$

$15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0$

$\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0$

$x=0\text{ (or) }x=3\text{ (or) }x=-2$

Therefore, the zeros of our given function are $x=-2,0,3$ .

7 0

3 years ago

Find the value of 2 - 3x when x = 7 PLEASE HELP ME :(

Sergio [31]

Answer:

-19

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

1 <br>-6a × - <br> 2 <br>Another time :/ , I'm studying for my post mid term exams..

Zepler [3.9K]

Answer:

<em>a×</em>

<em>a×_</em>

<em>a×_12 </em>

Step-by-step explanation:

1

_

-6

_

2

6×2=12

a×

_

6

_

2

ax

_12

8 0

2 years ago

The function graphed above is:

dem82 [27]

Step-by-step explanation:

When the slope of the function is positive, it is increasing

when the slope of the function is negative, it is decreasing

just like with the line function y = mx + b

so if you put a line tangent to the function at every point the slope of the line will indicate a increasing or decreasing point of the function

also beware where the slope is zero it is not increasing or decreasing

there are two intervals of increasing, one interval of decreasing and two point of zero slope or neither increasing or decreasing

increasing interval 1) x < -2 2) x > 1.5

decreasing interval 1) -2 < x < 1.5

at -2 and 1.5 the slope is zero

5 0

2 years ago