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BARSIC [14]
3 years ago
14

You go to order ice cream sundae and there are lots of options! Each sundae includes one flavor of ice cream and one topping .Th

ere is strawberry, vanilla, and chocolate ice cream. You also get the choice of a topping. There are sprinkles, hot fudge, whipped cream or cookie crumbs. If you were to chose a sundae at random, find each probability.
1) P(Chocolate, sprinkles)

2) P( Vanilla, hot fudge)

3) P( Strawberry, cookie crumbs)
Mathematics
1 answer:
Naddik [55]3 years ago
4 0

Answer:

2.) P(Chocolate, sprinkles)

Step-by-step explanation:

A lot of people choose chocolate ice cream over other flavors, and a lot of people also like sprinkles on their ice cream.

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4 0
2 years ago
Sanjay had a case of 24 bottles of water. In the first week Sanjay drank 3/8 of the bottles of water. In the second week Sanjay
Gnom [1K]

Answer:

The answer to your question is: 5 bottles

Step-by-step explanation:

Process

First week

Divide 24 by 8

                        24/8 = 3 bottles = 1/8

                        but Sanjay drank 3/8 = 9 bottles

And there are 24 - 9 bottles left = 15

- Second week

Divide 15 by 3

                       15/3 = 5 then 5 bottles = 1/3

                       but sanjay drank 2/3 = 10 bottles

Then, there are 15 - 10 bottles left  = 5

                         

8 0
3 years ago
there tiger barbs in a 15 gallon aquarium and giant dani is in a 30 gallon aquarium.what numerical expression to represent the g
Eva8 [605]
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3 0
3 years ago
Find the value of kk for which the constant function x(t)=kx(t)=k is a solution of the differential equation 5t3dxdt+2x−2=05t3dx
uranmaximum [27]
Given the differential equation

5t^3 \frac{dx}{dt} +2x-2=0

The solution is as follows:

5t^3 \frac{dx}{dt} +2x-2=0 \\  \\ \Rightarrow5t^3 \frac{dx}{dt} =2-2x \\  \\ \Rightarrow \frac{5}{2-2x} dx= \frac{1}{t^3} dt \\  \\ \Rightarrow \int {\frac{5}{2-2x} } \, dx = \int {\frac{1}{t^3}} \, dt \\  \\ \Rightarrow- \frac{5}{2} \ln(2-2x)=- \frac{1}{2t^2} +A \\  \\ \Rightarrow\ln(2-2x)= \frac{1}{5t^2} +B\\  \\ \Rightarrow2-2x=Ce^{\frac{1}{5t^2}} \\  \\ \Rightarrow 2x=Ce^{\frac{1}{5t^2}}+2 \\  \\ \Rightarrow x=De^{\frac{1}{5t^2}}+1
3 0
3 years ago
Giving brainlistto the right answer
Mrac [35]

Answer:

-19 <  -18

-19 < -17

-19 < -16

hope this helps

have a good day :)

Step-by-step explanation:

4 0
3 years ago
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