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3 years ago

Calculate the speed of a wave with the frequency of 100 hz and wavelength of 250 m, please.

Mathematics

1 answer:

masya89 [10]3 years ago

7 0

Answer:

25000m/s

Step-by-step explanation:

The following formula is used to calculate the speed or velocity of a wave.

V = f * w

Where V is the velocity (m/s)

f is the frequency (hz)

w is the wavelength (m)

First, determine the frequency.

Calculate the frequency of the wave.

Next, determine the wavelength.

Calculate the wavelength of the wave.

Finally, calculate the wave speed.

Using the formula above, calculate the wave speed.

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Simplify expressions 2y(y+3)+4y(y-1)

svlad2 [7]

Answer:

6y^2+2y

Step by step explanation:

2y*(y+3)+4y*(y-1)

Distribute 2y through the parentheses

2y^2+6y+4y*(y-1)

Distribute 4y through the parentheses

2y^2+6y+4y^2-4y

Collect like terms

6y^2+6y-4y

Collect like terms

6y^2+2y

Answer

6y^2+2y

6 0

2 years ago

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What number solves the equation x9=4?

MissTica

ANSWER: x=4/9
correct me if im wrong

5 0

3 years ago

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A radio antenna is kept perpendicular to the ground by three wires of equal length. The wires touch the ground at three points o

Elena-2011 [213]

Answer:

The coordinates of the base of the antenna is (-6. 1)

Step-by-step explanation:

Here we are required to find the center of a circle given points on the circumference

The equation of a circle is

(x - h)² + (y - k)² = r²

Where:

x and y are points on the circumference

h and k are coordinates of the center of the circle and

r = The radius of the circle

Since we have the values for the points on the circumference, we are left with three unknowns, which we can find with three equations as follows;

By plugging in the values for x and y at the respective points we get,

At (9, -19) → (9 - h)² + (-19 - k)² = r²...............(1)

At (-21, -19) → (-21 - h)² + (-19 - k)² = r².....,...(2)

At (14, 16 ) → (14 - h)² + (16 - k)² = r² ............(3)

Solving, we get from (1) (-19 - k)² = r² - (9 - h)²

Plugging in the value of (-19 - k)² in equation (2) we get

(-21 - h)² + r² - (9 - h)² = r²

So that (-21 - h)² - (9 - h)² = r² - r² = 0

and (-21 - h)² - (9 - h)² = 0 gives

60·h +360 = 0 or h = -6

Plugging in the value of h = -6 in equation (3) we get

(14 - (-6))² + (16 - k)² = r²

20² + (16 - k)² = r² .................(4)

similarly from equation (1) we get

(9 - (-6))² + (-19 - k)² = r²

15² + (-19 - k)² = r² ................(5)

Subtracting equation (5) from (4) gives

20² - 15² + (16 - k)² - (-19 - k)² = 0

Which gives

-70·k + 70 = 0

or k = 1

Therefore the coordinates of the base of the antenna = (-6. 1).

6 0

3 years ago

Both sets of values have an average of 13. Is Set A's standard deviation smaller, larger, or about the same as Set B's? (Note: T

polet [3.4K]

Hi there!

<u>Set A has a LARGER standard deviation. </u>

A set's standard deviation is equivalent to:

$\sigma = \frac{\sqrt{\Sigma (x - \mu)^2 }}{n-1}$

σ = standard deviation

x = value

μ = mean

n = # of observations

Basically, standard deviation is calculated using how far apart EACH value is from the set's mean. If more values are FARTHER away from the mean, the standard deviation increases and vice-versa.

Set A has a GREATER RANGE and its values are farther from 13 on both sides compared to Set B which has a SMALLER RANGE and its values are closer to 13.

Therefore, Set A will have a larger standard deviation.

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3 years ago

Geometry math question

Veseljchak [2.6K]

Use my photo to see the work and answers! Hope this helped :)

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3 years ago

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