Question

Find the distance between the points given. (-3, 0) and (0, √7) √2 4 √(13)

Answer 1

Answer:

4

Step-by-step explanation:

Remember that to find the distance between any two points on the plane, we should use the distance formula:

$d=\sqrt{(x_2-x_1)+(y_2-y_1)}$

where

$(x_1,y_1)$ are the coordinates of the first point

$(x_2,y_2)$ are the coordinates of the second point

We know from our problem that the first point is (-3, 0); therefore, $x_1=-3$ and $y_1=0$. We also know that the second point is (0, √7), so $x_2=0$ and $y_2=\sqrt{7}$.

Replacing the values:

$d=\sqrt{(x_2-x_1)+(y_2-y_1)}$

$d=\sqrt{(0-(-3))^2+(\sqrt{7}-2)^2 }$

$d=\sqrt{(0+3)^2+(\sqrt{7})^2 }$

$d=\sqrt{(3)^2+7}$

$d=\sqrt{9+7}$

$d=\sqrt{16}$

$d=4$

We can conclude that the distance between the given points is 4.

Answer 2

Answer:

The correct answer is second option 4

Step-by-step explanation:

Distance formula

Let (x₁, y₁) and (x₂, y₂) be the two points, the distance between two points is given by,

Distance = √[(x₂ - x₁)² + (y₂ - y₁)²]

It is given two points (-3, 0) and (0, √7)

To find the distance

Distance =  √[(x₂ - x₁)² + (y₂ - y₁)²]  =  √[(0 - - 3)² + (√7 - 0)²]

  = √[(0 + 3)² + (√7)²]  =√[(3)² + (√7)²]  

  = √(9 + 7) = √16 = 4

Therefore the correct answer is 4