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3 years ago

What are the domains and ranges of the graphs

Mathematics

1 answer:

Maslowich3 years ago

7 0

Answer:

The domain for graph 1 is all real numbers, the range is y >= 0.

The domain for graph 2 is x >= 0, the range is y >= 0

Step-by-step explanation:

Graph 1: The x values are infinite for the graph, the y values will always be above zero and continue to be infinite.

Graph 2: The x values start at 0 and go to the right for infinity, the y values start at 0 and continue to infinity.

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7. The ordered pairs ((-1,-9), (5,9). (7.15)) are included in which function?<br> 14

Sholpan [36]

Answer:

C. y=3x-6

Step-by-step explanation:

6 0

3 years ago

PLEASE HELP<br><br>divide. (3x-2)(x-4)-(x-4)(6-5x)<br>/(4-x)(8x-1)

8_murik_8 [283]

Answer:

x = 39/74 - sqrt(1817)/74 or x = 39/74 + sqrt(1817)/74

Step-by-step explanation:

Solve for x:

(x - 4) (3 x - 2) - ((6 - 5 x) (x - 4) (8 x - 1))/(4 - x) = 0

Simplify and substitute y = 4 - x.

(x - 4) (3 x - 2) - ((6 - 5 x) (x - 4) (8 x - 1))/(4 - x) = -434 + 257 (4 - x) - 37 (4 - x)^2

= -37 y^2 + 257 y - 434:

-37 y^2 + 257 y - 434 = 0

Divide both sides by -37:

y^2 - (257 y)/37 + 434/37 = 0

Subtract 434/37 from both sides:

y^2 - (257 y)/37 = -434/37

Add 66049/5476 to both sides:

y^2 - (257 y)/37 + 66049/5476 = 1817/5476

Write the left hand side as a square:

(y - 257/74)^2 = 1817/5476

Take the square root of both sides:

y - 257/74 = sqrt(1817)/74 or y - 257/74 = -sqrt(1817)/74

Add 257/74 to both sides:

y = 257/74 + sqrt(1817)/74 or y - 257/74 = -sqrt(1817)/74

Substitute back for y = 4 - x:

4 - x = 257/74 + sqrt(1817)/74 or y - 257/74 = -sqrt(1817)/74

Subtract 4 from both sides:

-x = sqrt(1817)/74 - 39/74 or y - 257/74 = -sqrt(1817)/74

Multiply both sides by -1:

x = 39/74 - sqrt(1817)/74 or y - 257/74 = -sqrt(1817)/74

Add 257/74 to both sides:

x = 39/74 - sqrt(1817)/74 or y = 257/74 - sqrt(1817)/74

Substitute back for y = 4 - x:

x = 39/74 - sqrt(1817)/74 or 4 - x = 257/74 - sqrt(1817)/74

Subtract 4 from both sides:

x = 39/74 - sqrt(1817)/74 or -x = -39/74 - sqrt(1817)/74

Multiply both sides by -1:

Answer: x = 39/74 - sqrt(1817)/74 or x = 39/74 + sqrt(1817)/74

7 0

3 years ago

The total cost to rent 5 chairs and 3 tables is $27. The total cost to rent 2 chairs and 12 tables is $81. What is the cost to r

kati45 [8]

The cost to rent each chair is $1.5 and cost to rent each table is $6.5

<h3>Applications of systems of linear equations </h3>

From the question, we are to determine the cost to rent each chair and each table

Let c represent chair

and

t represent table

From the given information,

The total cost to rent 5 chairs and 3 tables is $27

That is,

5c + 3t = 27 ------------ (1)

Also,

The total cost to rent 2 chairs and 12 tables is $81

That is,

2c + 12t = 81 ---------- (2)

Now, solve the equations simultaneously

5c + 3t = 27 ------------ (1)

2c + 12t = 81 ---------- (2)

Multiply equation (1) by 2 and multiply equation (2) by 5

2 × [5c + 3t = 27 ]

5 × [2c + 12t = 81 ]

10c + 6t = 54 ------------- (3)

10c + 60t = 405 ------------- (4)

Subtract equation (4) from equation (3)

10c + 6t = 54

10c + 60t = 405

---------------------------

-54t = -351

t = -351/-54

t = 6.5

Substitute the value of t into equation (2)
2c + 12t = 81

2c + 12(6.5) = 81

2c + 78 = 81

2c = 81 - 78

2c = 3

c = 3/2

c = 1.5

∴ The cost of chair is $1.5 and cost of table is $6.5

Hence, the cost to rent each chair is $1.5 and cost to rent each table is $6.5

Learn more on Solving system of linear equations here: brainly.com/question/13729904

#SPJ1

8 0

2 years ago

Solve the system of equations by graphing. x+y=-9 4x+y=-19

shutvik [7]

For this case we have the following system of equations:

$x + y = -9\\4x + y = -19$

We multiply the first equation by -4:

$-4x-4y = 36$

We have the following equivalent system of equations:

$-4x-4y = 36\\4x + y = -19$

We add the equations:

$-4x + 4x-4y + y = 36-19\\-3y = 17\\y = - \frac {17} {3}$

We find the value of the variable "x":

$x = -9-yx = -9 - (- \frac {17} {3})\\x = -9 + \frac {17} {3}\\x = \frac {-27 + 17} {3}\\x = - \frac {10} {3}$

Thus, the solution of the system is:

$(x, y): (- \frac {10} {3}, - \frac {17} {3})$

See the graphic in the attached image

ANswer:

$(x, y): (- \frac {10} {3}, - \frac {17} {3})$

See the graphic in the attached image

4 0

4 years ago

PLEASEE HELPP!!!

Mandarinka [93]

Answer:

AB/DE=BC/EF=AC/DF

Step-by-step explanation:

Corresponding segments are designated by letters in corresponding positions in the triangle names. For example, of one segment is designated using the 1st and 2nd letters of one triangle name (such as AB), then the corresponding segment is designated using the 1st and 2nd letters of the other triangle name (such as DE).

Corresponding segments are proportional in length. Corresponding angles are congruent.

6 0

3 years ago

Read 2 more answers