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3 years ago

Write an equation for the sentence. The product of some number and five is added to seven to give a total of twenty-three.

Mathematics

1 answer:

neonofarm [45]3 years ago

5 0

Hello!

We could write this equation as shown below.

5x+7=23

As you can see, your answer will be D) 5x+7=23

I hope this helps!

You might be interested in

Which sequence shows the numbers in order from least to greatest? A. -2/3 , 1/5 , -3/4 B. 1/5 , -2/3 , -3/4 C. -3/4 , -2/3 , 1/5

Rom4ik [11]

Answer:

C. -3/4, -2/3, 1/5

Step-by-step explanation:

Just from observation, you can tell the 1/5 will be the greatest because all the other fractions are negative. Then, I converted them to decimal form to make it easier.

-2/3 = -0.6666666 (the 6 goes on forever)

-3/4 = -0.75

1/5= 0.20

Then, you put them in order.

-3/4 would be the least .

Followed by, -2/3

Finally, 1/5

7 0

3 years ago

- 4/7 • (- 3/4) <br> Find the product simplify if possible

Reil [10]

Answer:

I believe the answer is 3/7. Hope this helps!

Step-by-step explanation:

4 0

3 years ago

Question 1 (Essay Worth 10 points)

il63 [147K]

Answer:

Part A. x = 1/26 Part B. x = 1/50

Step-by-step explanation:

Solve for x:

26 x = 1

Divide both sides by 26:

Answer: x = 1/26

___________________

Solve for x:

50 x = 1

Divide both sides by 50:

Answer: x = 1/50

8 0

3 years ago

Jacinta is working on a jigsaw puzzle that has 403 pieces. She has completed 1/4 of the puzzle. About how many pieces has she pl

slava [35]

$403 / 4 = 100.75$
to get any fraction of a number, as long as the numerator is 1 in the fraction, just divide by the denominator. In this case it's 4. Since you can't place .75 of a puzzle piece, she's placed 100 pieces in the puzzle.

4 0

3 years ago

3x+-2y=-6<br> 5x-2y=7<br> how do i solve this Elimination pls

tatuchka [14]

Answer:

$x=\frac{13}{2}, y=\frac{51}{4}$

Step-by-step explanation:

$We\ are\ given,\\3x-2y=-6\\5x-2y=7\\Considering\ this\ system\ of\ equations,\\Let\ 3x-2y=-6\ be\ E_1\\Let\ 5x-2y=7\ be\ E_2,\\Hence,\\Multiplying\ E2\ with\ -1, we\ get:\\3x-2y=-6\\-1(5x-2y)=7*-1\\Hence,\\3x-2y=-6\\-5x+2y=-7\\Now,\\Lets\ add\ E_1\ and\ E_2\ together\\Hence,\\(3x-2y)+(-5x+2y)=(-6)+(-7)\\Hence,\\3x-2y-5x+2y=-13\\Arranging\ And\ Adding\ Like\ terms,\ we\ have:\\3x-5x-2y+2y=-13\\Hence,\\-2x+0y=-13\\-2x=-13\\x=\frac{-13}{-2}=\frac{13}{2}$

$Now,\ we\ can\ substitute\ x=\frac{13}{2}\ in\ E_1\ or\ E_2,\\But,\\Here,\ we'll\ substitute\ it\ in\ E1,\\Hence,\\Substituting\ x=\frac{13}{2}\ in\ E1,\ we\ have:\\3*\frac{13}{2}-2y=-6\\\frac{39}{2}-2y=-6\\-2y=-6- \frac{39}{2}\\-2y=\frac{-12-39}{2}\\-2y=\frac{-51}{2}\\y=\frac{-51}{2*-2}=\frac{51}{4}\\Hence,\\x=\frac{13}{2}, y=\frac{51}{4}$

4 0

3 years ago