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Aleonysh [2.5K]

3 years ago

5

Write an equation for the sentence. The product of some number and five is added to seven to give a total of twenty-three.

1 answer:

neonofarm [45]3 years ago

5 0

Hello!

We could write this equation as shown below.

5x+7=23

As you can see, your answer will be D) 5x+7=23

I hope this helps!

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A food scientist takes a random sample of 25 cereals in order to test the claim that the mean fiber content is less than 2.5 gra

Jlenok [28]

Answer:

Choice A: there is insufficient evidence to conclude that the mean for the fiber content is less than 2.5 gms.

Step-by-step explanation:

From the graphs given the more appropriate is one sample t- test

One sample t- test is used and the results are

Hypothesis Test Fiber

Sample Mean 2.62

Sample St. Dev 3.492

Degrees of Freedom 24

t- test statistic 0.1718

p- value 0.5675

the critical region for this test at ∝= 0.05 is t < -1.711

There is not enough evidence to reject the null hypothesis.

Since the calculated t= 0.1718 does not fall in the critical region the null hypothesis is accepted that the mean fiber content is not less than 2.5 grams.T

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3 years ago

Which represents -5x + 4y > -1

miskamm [114]

Answer:

it's b :)

Step-by-step explanation:

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An online music club sells compact discs for $13.95 each plus $1.95 shipping and handling per order. If Maria's total bill was $

Alekssandra [29.7K]

The equation is 13.95x+1.95=85.65
The answer is 6 compact discs.

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These the answers ❤️.

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No ❤️ hahaha i can’t see anything

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The sum of two terms of gp is 6 and that of first four terms is 15/2.Find the sum of first six terms.

Gnoma [55]

Given:

The sum of two terms of GP is 6 and that of first four terms is $\dfrac{15}{2}.$

To find:

The sum of first six terms.

Solution:

We have,

$S_2=6$

$S_4=\dfrac{15}{2}$

Sum of first n terms of a GP is

$S_n=\dfrac{a(1-r^n)}{1-r}$ ...(i)

Putting n=2, we get

$S_2=\dfrac{a(1-r^2)}{1-r}$

$6=\dfrac{a(1-r)(1+r)}{1-r}$

$6=a(1+r)$ ...(ii)

Putting n=4, we get

$S_4=\dfrac{a(1-r^4)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1-r^2)(1+r^2)}{1-r}$

$\dfrac{15}{2}=\dfrac{a(1+r)(1-r)(1+r^2)}{1-r}$

$\dfrac{15}{2}=6(1+r^2)$ (Using (ii))

Divide both sides by 6.

$\dfrac{15}{12}=(1+r^2)$

$\dfrac{5}{4}-1=r^2$

$\dfrac{5-4}{4}=r^2$

$\dfrac{1}{4}=r^2$

Taking square root on both sides, we get

$\pm \sqrt{\dfrac{1}{4}}=r$

$\pm \dfrac{1}{2}=r$

$\pm 0.5=r$

Case 1: If r is positive, then using (ii) we get

$6=a(1+0.5)$

$6=a(1.5)$

$\dfrac{6}{1.5}=a$

$4=a$

The sum of first 6 terms is

$S_6=\dfrac{4(1-(0.5)^6)}{(1-0.5)}$

$S_6=\dfrac{4(1-0.015625)}{0.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Case 2: If r is negative, then using (ii) we get

$6=a(1-0.5)$

$6=a(0.5)$

$\dfrac{6}{0.5}=a$

$12=a$

The sum of first 6 terms is

$S_6=\dfrac{12(1-(-0.5)^6)}{(1+0.5)}$

$S_6=\dfrac{12(1-0.015625)}{1.5}$

$S_6=8(0.984375)$

$S_6=7.875$

Therefore, the sum of the first six terms is 7.875.

5 0

3 years ago