In three dimensions, the cross product of two vectors is defined as shown below

Then, solving the determinant

In our case,

Where we used the formula for AxB to calculate ixj.
Finally,

Thus, (i+j)x(ixj)=i-j
I think it's d hope it helps
Answer:
1 and 7 are congruent
2 and 5 are supplementary
4 and 6 are congruent
3 and 8 are supplementary
Answer:
2132c1 23
Step-by-step explanation:
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Answer:
1
Step-by-step explanation:
x-7=-5x-1
x-(-5x)-7=-1
x+5x-7=-1
6x-7=-1
6x=-1+7
6x=6
x=6/6
x=1