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Vadim26 [7]
3 years ago
5

What is 95 percent of 800

Mathematics
2 answers:
Levart [38]3 years ago
7 0

Answer:

The answer is 760

Step-by-step explanation:

.95×800=760

tangare [24]3 years ago
3 0

Answer:

760!!!

HOPE THIS HELPSS!!!

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A bag contains 20 blue blocks, 10 red blocks, 5 white blocks, and 5 green blocks. Find P(red). *
Mashutka [201]

Answer:

Step-by-step explanation:

total =20

red=10

P(red)=10/20=1/2

7 0
3 years ago
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Use the properties of addition to simplify 10v – 4s – 6v +8s.
Bumek [7]

We have that Using strictly  the properties of addition to simplify

10v-6v+4s

From the question we are told

Use the properties of addition to simplify 10v – 4s – 6v +8s.

Generally the equation for the  Statement  is mathematically given as

10v – 4s – 6v +8s.

Therefore

WE collect like terms

10v – 4s – 6v +8s.

10v-6v-4s+8s

Therefore Using strictly  the properties of addition to simplify

We have

10v-6v-4s+8s

10v-6v+4s

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7 0
2 years ago
Which speed is the fastest?
Schach [20]

Answer:

C, 180 miles/ 3 hours

Step-by-step explanation:

C is the correct answer because you need to find the unit rate of all of the numbers.

A. = 30 mph

B. = 45 mph

C. = 60 mph

D. = 40 mph

Therefore, C is the fastest.

4 0
3 years ago
The sum of four times a number and 18 is the same as the difference of fourteen and twice a number
Citrus2011 [14]
4x+18=14-2x \\ 4x=-4-2x \\ 6x=-4 \\ x= \frac{2}{3}
4 0
4 years ago
The probability that a single radar station will detect an enemy plane is 0.65.
taurus [48]

Answer:

a) We need 4 stations to be 98% certain that an enemy plane flying over will be detected by at least one station.

b) If seven stations are in use, the expected number of stations that will detect an enemy plane is 4.55.

Step-by-step explanation:

For each station, there are two two possible outcomes. Either they detected the enemy plane, or they do not. This means that we can solve this problem using concepts of the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem, we have that:

The probability that a single radar station will detect an enemy plane is 0.65. This means that n = 0.65.

(a) How many such stations are required to be 98% certain that an enemy plane flying over will be detected by at least one station?

This is the value of n for which P(X = 0) \leq 0.02.

n = 1.

P(X = 0) = C_{1,0}.(0.65)^{0}.(0.35)^{1} = 0.35

n = 2

P(X = 0) = C_{2,0}.(0.65)^{0}.(0.35)^{2} = 0.1225

n = 3

P(X = 0) = C_{3,0}.(0.65)^{0}.(0.35)^{3} = 0.0429

n = 4

P(X = 0) = C_{4,0}.(0.65)^{0}.(0.35)^{4} = 0.015

We need 4 stations to be 98% certain that an enemy plane flying over will be detected by at least one station.

(b) If seven stations are in use, what is the expected number of stations that will detect an enemy plane?

The expected number of sucesses of a binomial variable is given by:

E(x) = np

So when n = 7

E(x) = 7*(0.65) = 4.55

If seven stations are in use, the expected number of stations that will detect an enemy plane is 4.55.

6 0
3 years ago
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