t (23) ≤ 97 - 23
The minus 23 at the back represents the feet she already descended before what the question wants us to calculate
≤ is used instead of < because it states more than, not "equal or more than" (meaning 97 sharp is fine)
The answer is I think b because it has x-50 and it said Andrew sold less that Sarah so its subtracting
The height at t seconds after launch is
s(t) = - 16t² + V₀t
where V₀ = initial launch velocity.
Part a:
When s = 192 ft, and V₀ = 112 ft/s, then
-16t² + 112t = 192
16t² - 112t + 192 = 0
t² - 7t + 12 = 0
(t - 3)(t - 4) = 0
t = 3 s, or t = 4 s
The projectile reaches a height of 192 ft at 3 s on the way up, and at 4 s on the way down.
Part b:
When the projectile reaches the ground, s = 0.
Therefore
-16t² + 112t = 0
-16t(t - 7) = 0
t = 0 or t = 7 s
When t=0, the projectile is launched.
When t = 7 s, the projectile returns to the ground.
Answer: 7 s
Answer:
The answer to your question is: letter A
Step-by-step explanation:
Rules for using scientific notation:
1.- The number before the decimal point must be between 1 and 10.
2.- Determine the exponent
3.- It must be in decimal format, ( x 10)
A 3.8*10^12 This number is in correct scientific notation.
B 33.8* 10 This number is incorrect, because before the decimal point the number must be between 1 and 10.
C 3.8 *20^8 This number is incorrect because the power must be 10 not 20.
Answer:
0.555555556
Step-by-step explanation: