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siniylev [52]
3 years ago
13

Arrange these numbers from least to greatest:

Mathematics
1 answer:
zmey [24]3 years ago
8 0
First let's put them all over 100.
-\frac{5}{8} would change to -\frac{62.5}{100}

-\frac{7}{9} to -\frac{77.7}{100}

-\frac{4}{5} to -\frac{80}{100}

-\frac{3}{7} to -\frac{42.8}{100}

Then if we put them from least to greatest it would be from highest to lowest (since they are negatives)

-\frac{4}{5}, -\frac{7}{9}, -\frac{5}{8}, -\frac{3}{7}

The answer would be B


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Solve for m.<br> m+9=-2<br><br> m=?
amm1812
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subtract 9 to both sides
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3 years ago
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For the parallelogram, if mZ2 = 52 — 28 and mZ4 = 32 –<br> 10, find m23
exis [7]

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answer is b just had this problem lol

Step-by-step explanation:

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3 years ago
There are three consecutive integers, such that six times the first, minus two times the second, equals the third integer plus f
frozen [14]

Answer:

3

Step-by-step explanation:

Given that:

Integers : x, x + 1, x + 2

6x - 2(x + 1) = (x+2) + 5

6x - 2x - 2 = x + 2 + 5

4x - 2 = x + 7

4x - x = 7 + 2

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x = 9/3

x = 3

First integer = x = 3

2nd integer = x + 1 = 3+1 = 4

3rd Integer = x + 1 + 1 = 3 + 2 = 5

7 0
3 years ago
What is y=4/5x+2 written in standard form
shepuryov [24]

Answer:

4x-5y=-10

Step-by-step explanation:

we know that

The equation of the line in standard form is in the form

Ax + By = C

where

A is a positive integer, and B, and C are integers

In this problem we have

y=\frac{4}{5}x+2 ----> equation of the line in slope intercept form

Convert to standard form

Multiply by 5 both sides

5y=4x+10

4x-5y=-10

5 0
3 years ago
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The meat department of a local supermarket packages ground beef using meat trays of two sizes: 1 designed to hold 1 lb of meet a
r-ruslan [8.4K]

Answer:

c) 0.932

99% confidence interval for average weights of all packages sold in small meat trays.

(0.932 ,1.071)

Step-by-step explanation:

Explanation:-

Given random sample of 35 packages in small meat trays produced weight with an average of 1.01 lbs. and standard deviation  of 0.18 lbs.

size of the sample 'n' = 35

mean of the sample x⁻= 1.01lbs

standard deviation of the sample 'S' = 0.18lbs

<u>The 99% confidence intervals are given by</u>

(x^{-} - t_{\alpha } \frac{S}{\sqrt{n} } , x^{-} +t_{\alpha } \frac{S}{\sqrt{n} } )

The degrees of freedom γ=n-1 =35-1=34

tₐ =  2.0322

99% confidence interval for average weights of all packages sold in small meat trays

(1.01 - 2.0322 \frac{0.18}{\sqrt{35} } , 1.01+2.0322 \frac{0.18}{\sqrt{35} } )

( 1.01 - 0.06183 , 1.01+0.06183)

(0.932 ,1.071)

<u>Final answer</u>:-

<u>99% confidence interval for average weights of all packages sold in small meat trays.</u>

<u>(0.932 ,1.071)</u>

5 0
3 years ago
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