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Ede4ka [16]
3 years ago
8

How do I fill this out? Im not sure how to?

Mathematics
1 answer:
prohojiy [21]3 years ago
5 0

Answer:

z=-21

Step-by-step explanation: (9-3)/2=(6+z)/5

We move all terms to the left:

(9-3)/2-((6+z)/5)=0

We add all the numbers together, and all the variables

-((z+6)/5)+6/2=0

We add all the numbers together, and all the variables

-((z+6)/5)+3=0

We multiply all the terms by the denominator

-((z+6)+3*5)=0

We calculate terms in parentheses: -((z+6)+3*5), so:

(z+6)+3*5

We add all the numbers together, and all the variables

(z+6)+15

We get rid of parentheses

z+6+15

We add all the numbers together, and all the variables

z+21

Back to the equation:

-(z+21)

We get rid of parentheses

-z-21=0

We add all the numbers together, and all the variables

-1z-21=0

We move all terms containing z to the left, all other terms to the right

-z=21

z=21/-1

z=-21

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One of our brainliest, Konrad509, made this:
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\dfrac{B_x \sqrt{74_x}}{1D_x}+J_x51_x=4G3_x

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\dfrac{11\cdot x^0\cdot \sqrt{7\cdot x^1+4\cdot x^0}}{1\cdot x^1+13\cdot x^0}+19\cdot x^0\cdot (5\cdot x^1+1\cdot x^0)=4\cdot x^2+16\cdot x^1+3\cdot x^0\\\\\dfrac{11\sqrt{7x+4}}{x+13}+19(5x+1)=4x^2+16x+3\\\\\dfrac{11\sqrt{7x+4}}{x+13}+95x+19=4x^2+16x+3\\\\11\sqrt{7x+4}+95x(x+13)+19(x+13)=(4x^2+16x+3)(x+13)\\\\11\sqrt{7x+4}+95x^2+1235x+19x+247=4x^3+52x^2+16x^2+208x+3x+39\\\\11\sqrt{7x+4}=4x^3-27x^2-1043x-208\\\\121(7x+4)=(4x^3-27x^2-1043x-208)^2

121(7x+4)=(4x^3-27x^2-1043x-208)^2\\\\847x+484=16 x^6 - 216 x^5 - 7615 x^4 + 54658 x^3 + 1099081 x^2 + 433888 x + 43264\\\\16 x^6 - 216 x^5 - 7615 x^4 + 54658 x^3 + 1099081 x^2 + 433041 x +42780=0

Now, the "only" thing that remains to do is solving the above equation.

While making this problem I only made sure it has a solution. I didn't try to solve it myself and I didn't know it will end up with such "convoluted" polynomial. Sorry to everyone who tried to solve it... m(_ _)m

I think the best way to approach it is using the rational root theorem since we know that x\in\mathbb{N}. Moreover we can deduce that x\geq19 since there is J and J=19.

After you succesfully solve it, you should get the answer x=20.

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