Which standard is this there are many ways i mean some different ways !
<span>expressions for the mean and standard deviation of y if this variable is determined by the expression y
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Solution:- Given numbers to compare are 512 and 521 .
As they are 3 digit numbers
So, we have to compare hundreds place.
But hundreds are equal in both the numbers with digit 5.
Next we have to compare tens place.
Case 1 :- 1 ten is smaller in 512 than 2 tens in 521 .
So we get the result that,
512 is smaller than 521
or <em> 512 < 521</em>
Case 2:-2 tens is greater in 521 than 1 ten in 512 .
So we get the result that,
521 is greater than 512
or <em> 521 > 512</em>
Answer:
y/2 = 9
In order to find the value of y, we must first isolate y by performing inverse operations.
Right now, y is being divided by 2, so the inverse operation of division is multiplication.
So we multiply by 2 on both sides:
y/2 = 9
*2 *2
2/2y = 18
y = 18
