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Troyanec [42]
3 years ago
7

Subtract (5x^2-5) from the sum (x^2-9x+2) and (4x^2-5x+1)

Mathematics
1 answer:
Ivan3 years ago
3 0

Assignment: \bold{Solve \ Equation: \ \left(x^2-9x+2\right)+\left(4x^2-5x+1\right)-\left(5x^2-5\right)}

<><><><><><><>

Answer: \boxed{\bold{-14x+8}}

<><><><><><><>

Explanation: \downarrow\downarrow\downarrow

<><><><><><><>

[ Step One ] Remove Parenthesis: (a) = a

\bold{x^2-9x+2+4x^2-5x+1-\left(5x^2-5\right)}

[ Step Two ] Simplify \bold{-\left(5x^2-5\right)}

\bold{-5x^2+5}

[ Step Three ] Rewrite Equation

\bold{x^2-9x+2+4x^2-5x+1-5x^2+5}

[ Step Four ] Simplify \bold{x^2-9x+2+4x^2-5x+1-5x^2+5}

\bold{-14x+8}

<><><><><><><>

\bold{\rightarrow Mordancy \leftarrow}

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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The graph of y=f(x) is the solid black graph below. Which function represents the dotted graph?
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=============================================================

Explanation:

Let's focus on only the left-most points of each curve

For the black semicircle, the left-most point is located at (-7,0). The corresponding point on the red semicircle is at (-3,-1)

To go from (-7,0) to (-3,-1), we will do two things

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This can be done in any order. The action of "shift 4 units to the right" is effectively the same as shifting the xy axis 4 units to the left while keeping the curves fixed in place. This gives the illusion of movement. When we shift 4 the xy axis 4 units to the left, we're replacing each x input with x-4 as the new input.

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