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4 years ago

Subtract (5x^2-5) from the sum (x^2-9x+2) and (4x^2-5x+1)

Mathematics

1 answer:

Ivan4 years ago

3 0

Assignment: $\bold{Solve \ Equation: \ \left(x^2-9x+2\right)+\left(4x^2-5x+1\right)-\left(5x^2-5\right)}$

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Answer: $\boxed{\bold{-14x+8}}$

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Explanation: $\downarrow\downarrow\downarrow$

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[ Step One ] Remove Parenthesis: (a) = a

$\bold{x^2-9x+2+4x^2-5x+1-\left(5x^2-5\right)}$

[ Step Two ] Simplify $\bold{-\left(5x^2-5\right)}$

$\bold{-5x^2+5}$

[ Step Three ] Rewrite Equation

$\bold{x^2-9x+2+4x^2-5x+1-5x^2+5}$

[ Step Four ] Simplify $\bold{x^2-9x+2+4x^2-5x+1-5x^2+5}$

$\bold{-14x+8}$

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$\bold{\rightarrow Mordancy \leftarrow}$

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4 years ago

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3 years ago

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AlekseyPX

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4 years ago

In a recent month, 88% of automobile drivers filled their vehicles with regular gasoline, 2% purchased midgrade gas, and 10% bou

Nimfa-mama [501]

Answer:

b) 0.2464

c) 0.0580

d) 0.2952

Step-by-step explanation:

Probability of those that purchased regular gas = 88% = 0.88

2% purchased mid grade gas

10% purchased premium gad

Given that a driver bought regular gas, 28% paid with credit card

Given that a driver bought mid grade gas, 34% paid with credit card

Given that a driver bought premium gas, 42% paid with credit card

Let R represent drivers that bought regular gas

Let M represent drivers that bought mid grade gas

Let P represent drivers that bought premium gas

Let C represent credit card payment

Let NC represent non-credit card payment

Pr(R) = 88% = 0.88

Pr(M) = 2% = 0.02

Pr(P) = 10% = 0.10

Pr(C|R) = 28%= 0.28

Pr(C|M) = 34%= 0.34

Pr(C|P) = 42%= 0.42

Pr(NC|R) = 1 - 0.28= 0.72

Pr(NC|M) = 1 - 0.34 = 0.66

Pr(NC|P) = 1 - 0.42 = 0.58

Using multiplication rule

Pr(AnB) = Pr(A) * Pr(B|A) = Pr(B) * Pr(A|B)

Using conditional probability,

P(B|A) = Pr(AnB) / Pr(A)

Pr(CnR) = Pr(R) * Pr(C|R)

= 0.88*0.28

= 0.2464

Pr(CnM) = Pr(M) * Pr(C|M)

= 0.02*0.34

= 0.0068

Pr(CnP) = Pr(P) * Pr(C|P)

= 0.10*0.42

= 0.0420

b) the probability that an automobile driver filled with regular gasoline AND paid with a credit card =

Pr(CnR)

= 0.2464

c) the probability that an automobile driver filled with premium gasoline AND did NOT pay with a credit card = Pr(P n NC) = Pr(NC|P) * Pr(P)

= 0.58 * 0.10

= 0.0580

d) The probability of those that paid with credit card is given as

Pr(CnR) + Pr(CnM) + Pr(CnP)

= 0.2464 + 0.0068 + 0.042

= 0.2952

7 0

3 years ago