297/11 = 27
So we have 27 groups of 11 students. If there are 2 chaperones for every 11 students, then we can do:
27x2=54
There are 54 chaperones on the field trip.
Let us suppose number of rides is x.One ride costs $0.50.
Cost of x rides is 0.50x. The carnival charges is $5. Alex has $15 to spend .
Number of rides at most Alex can have can be given by the inequality:
0.50x+5≤ 15
To solve for x we subtract 5 both sides
0.50x≤ 15-5
0.50x≤ 10
Dividing both sides by 0.50 we have :
x≤ 20
Number of rides at most Alex can have is 20.
Answer:
1 is what percent of 52.6? = 1.9011406844106.
Step-by-step explanation:
urm google it that is what i did
Part 1:the answer is 1/36
each time we roll the dice, the whole probabilities are 6
if we roll it two times
6*6=36
part 2
it's 1/8
each time we flip a coin, the whole probabilities are 2
if we flip it 3 times
2*2*2=8
good luck
20,000 + 5,000 + 300 + 2 = 25302
25,302 x 1 = 25,302
24,000 + 1302 = 25302
25,000 + 302 = 25302
