Answer:
Step-by-step explanation:
-30n - 65 + 2 - 43
-30n - 63 - 43
-30n - 106
Answer:
I am assuming that you are talking about problem 2. so I will answer that.
Step-by-step explanation:
-2x + 6 ≥ 3x - 34
+2x +2x
6 ≥ 5x - 34
+34 + 34
40 ≥ 5x
÷5 ÷5
8 ≥ x
So, x can be anything equal to or less than 8.
Answer:
the rate of each train is 139 km/h and 159 km/h.
Step-by-step explanation:
let
v = the rate of the slower train
v + 20 = the rate of the faster train
d = 1490 km the distance that the two train will travel
t = 5 hr the time of the travel
since speed = distance/time => distance = speed*time
v*t + (v+20)t = d
5v + 5(v + 20) = 1490
5v+5(v+20)=1490
Step 1: Simplify both sides of the equation.
5v+5(v+20)=1490
5v+(5)(v)+(5)(20)=1490(Distribute)
5v+5v+100=1490
(5v+5v)+(100)=1490(Combine Like Terms)
10v+100=1490
10v+100=1490
Step 2: Subtract 100 from both sides.
10v+100−100=1490−100
10v=1390
Step 3: Divide both sides by 10.
10v/10 = 1390/10
v = 139km/h
Next
we add 139 to 20
139 + 20 = 159 km/h
the rate of each train is 139 km/h and 159 km/h.
