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4 years ago

Find the product. Write in simplest form. Keep answer as fraction - not decimal.

Mathematics

1 answer:

goldfiish [28.3K]4 years ago

5 0

X²z / 6xy

1x on top cancels 1x on bottom to give

xz / 6y

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arrange the expressions in the correct sequence to rationalize the denominator of the expression -(2)/(\sqrt(x+y-2)-\sqrt(x+y+2)

cupoosta [38]

We have to rationalize the denominator:
$\frac{-2}{ \sqrt{x+y-2} - \sqrt{x+y+2} } = \\ \frac{-2}{ \sqrt{x+y-2} - \sqrt{x+y+2} }* \frac{ \sqrt{x+y-2}+ \sqrt{x+y+2} }{ \sqrt{x+y-2}+ \sqrt{x+y+2} }= \\ \frac{-2*( \sqrt{x+y-2}+ \sqrt{x+y+2}) }{x+y-2-(x+y+2)}= \\ \frac{-2*( \sqrt{x+y-2}+ \sqrt{x+y+2}) }{x+y-2-x-y-2}= \\ \frac{-2*( \sqrt{x+y-2}+ \sqrt{x+y+2} }{-4}= \\ \frac{ \sqrt{x+y-2}+ \sqrt{x+y+2} }{2}$

6 0

3 years ago

Read 2 more answers

2. The cost of having a window fixed is $100 plus $20 per hour of labor. Using h for the number of hours of labor, write an expr

ahrayia [7]

Answer:

the third one

Step-by-step explanation:

I hope this helps with your question :)

5 0

3 years ago

Select all quantities that are proportional to the diagonal length of a square.

horsena [70]

Answer:

B. Perimeter of a square and

C. Side length of a square

Step-by-step explanation:

if n= side length of square then

Area of square is $n^{2}$
Perimeter of a square is 4×n
diagonal length of a square is $\sqrt{2}$ × n

Thus,

Perimeter of square can be expressed as

$2\sqrt{2}$ ×diagonal length of a square

Side length of a square can be expressed as

$\frac{1}{\sqrt{2} }$ ×diagonal length of a square

but Area of square is

$\frac{1}{\sqrt{2} }$ ×n×diagonal length of a square

As a Result, Area of square is <em>also dependent of the value n</em>, wheras in other cases it is <em>a proportion of diagonal length of a square</em>

5 0

3 years ago

What is the answer for question 1 and how

quester [9]

Step-by-step explanation:

ABC is an isoceles triangle (both legs are equally long). and AB is its baseline.

OC is now a median for ABC splitting the angle at C and AB in half.

so, we have 2 right-angled triangles : OAC and OBC.

the half-angles at C are 42/2 = 21°.

the angles at A and B are 90°.

and the half-angles at O are 180 - 90 - 21 = 69°.

remember that the sum of all angles in a triangle must always be 180°.

AB are the heights of both of these triangles.

the single height is sin(69)×7 = 6.535062985... cm

and so,

AB = 2× height = 13.07012597... cm.

4 0

2 years ago

Read 2 more answers

The combined math and verbal scores for students taking a national standardized examination for college admission, is normally d

kipiarov [429]

Answer:

The minimum score that such a student can obtain and still qualify for admission at the college = 660.1

Step-by-step explanation:

This is a normal distribution problem, for the combined math and verbal scores for students taking a national standardized examination for college admission, the

Mean = μ = 560

Standard deviation = σ = 260

A college requires a student to be in the top 35 % of students taking this test, what is the minimum score that such a student can obtain and still qualify for admission at the college?

Let the minimum score that such a student can obtain and still qualify for admission at the college be x' and its z-score be z'.

P(x > x') = P(z > z') = 35% = 0.35

P(z > z') = 1 - P(z ≤ z') = 0.35

P(z ≤ z') = 1 - 0.35 = 0.65

Using the normal distribution table,

z' = 0.385

we then convert this z-score back to a combined math and verbal scores.

The z-score for any value is the value minus the mean then divided by the standard deviation.

z' = (x' - μ)/σ

0.385 = (x' - 560)/260

x' = (0.385×260) + 560 = 660.1

Hope this Helps!!!

8 0

4 years ago