Answer:
0.57142
Step-by-step explanation:
A normal random variable with mean and standard deviation both equal to 10 degrees Celsius. What is the probability that the temperature at a randomly chosen time will be less than or equal to 59 degrees Fahrenheit?
We are told that the Mean and Standard deviation = 10°C
We convert to Fahrenheit
(10°C × 9/5) + 32 = 50°F
Hence, we solve using z score formula
z = (x-μ)/σ, where
x is the raw score = 59 °F
μ is the population mean = 50 °F
σ is the population standard deviation = 50 °F
z = 59 - 50/50
z = 0.18
Probability value from Z-Table:
P(x ≤59) = 0.57142
The probability that the temperature at a randomly chosen time will be less than or equal to 59 degrees Fahrenheit
is 0.57142
Answer:
Kahn academy works great with this stuff
Step-by-step explanation:
9514 1404 393
Answer:
47°
Step-by-step explanation:
The law of sines helps you find angle T. From there, you can find angle S.
sin(T)/t = sin(R)/r
sin(T) = (t/r)sin(R) = (10/20)sin(104°)
T = arcsin(sin(104°)/2) ≈ 29°
Then angle S is ...
S = 180° -R -T = 180° -104° -29°
∠S = 47°
Answer:
idk
Step-by-step explanation:
What you do you have to find someone more smarter than me!
First two are scalene last one is isosceles.
