Given:
bisects ∠RST.

To find:
The
.
Solution:
Since,
bisects ∠RST, therefore
...(1)
Now,

[Using (1)]

![[\text{Given }m\angle RSV=64^\circ]](https://tex.z-dn.net/?f=%5B%5Ctext%7BGiven%20%7Dm%5Cangle%20RSV%3D64%5E%5Ccirc%5D)

Therefore, the value of
is
.
Answer:
DC = 21 ; BC = 26
Step-by-step explanation:
The perimeter of a rectangle is given by :
P = 2(length + width)
2x + 3
3x - 1
Perimeter, P = 94
Hence,
94 = 2(2x +3 + (3x - 1))
94 = 2(2x + 3 + 3x - 1)
94 = 2(5x + 2)
94 = 10x + 4
94 - 4 = 10x
90 = 10x
x = 90 /10
x = 9
DC = 2x + 3 = 2(9) + 3 = 18 + 3 = 21
BC = 3x - 1 = 3(9) - 1 = 27 - 1 = 26
Prob of just quarter is 3/14 for a dime is 4/14 and for a nickel its 7/14
then all you do is multiply them all together to get 306122449/<span>10000000000 that took me way to long</span>
Answer:
The radius of a circumcircle of an equilateral triangle is equal to (a / √3), where ‘a’ is the length of the side of equilateral triangle.
Circle Radius = 16 / sq root (3)
Circle Radius = 9.237604307
Circle Area = PI * radius ^ 2
Circle Area = PI * 85.3333333333
Circle Area = 268.083
Equilateral Triangle area = side^2 * sq root (3) / 4
Equilateral Triangle area = 16^2 * 0.4330127019
Equilateral Triangle area = 110.85
Shaded region = 268.083 - 110.85
Shaded region = 157.233
Step-by-step explanation: