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Sloan [31]
2 years ago
12

Darren wins a coupon for $4 off the lunch special for each of five days he pays $75 for his 5 lunch specials write and solve an

equation to find the original price p four one lunch special.
P.s ur getting reported if you don't show all work and if you answer without an answer for the question
Mathematics
1 answer:
Valentin [98]2 years ago
8 0

The original price for one lunch special is $19.

<em><u>Explanation</u></em>

The original price for one lunch special is  'p'  dollar.

He wins a coupon for $4 off for each of five days. That means , <u>he needs to pay (p-4) dollar each day</u>.

So, the total amount needed to pay for 5 days = 5(p-4) dollar

Given that, <u>he pays $75 for his 5 lunch specials</u>. So the equation will be.....

5(p-4)= 75\\ \\ 5p-20=75\\ \\ 5p= 75+20\\ \\ 5p= 95\\ \\ p=\frac{95}{5}=19

So, the original price for one lunch special is $19.

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Answer:

Volume of the cylinder = 62.80 units^3

Step-by-step explanation:

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                                 =3.14*2*2*5\\\\=3.14*4*5\\\\=3.14*20\\\\=62.80units^3                              

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