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Sloan [31]
3 years ago
12

Darren wins a coupon for $4 off the lunch special for each of five days he pays $75 for his 5 lunch specials write and solve an

equation to find the original price p four one lunch special.
P.s ur getting reported if you don't show all work and if you answer without an answer for the question
Mathematics
1 answer:
Valentin [98]3 years ago
8 0

The original price for one lunch special is $19.

<em><u>Explanation</u></em>

The original price for one lunch special is  'p'  dollar.

He wins a coupon for $4 off for each of five days. That means , <u>he needs to pay (p-4) dollar each day</u>.

So, the total amount needed to pay for 5 days = 5(p-4) dollar

Given that, <u>he pays $75 for his 5 lunch specials</u>. So the equation will be.....

5(p-4)= 75\\ \\ 5p-20=75\\ \\ 5p= 75+20\\ \\ 5p= 95\\ \\ p=\frac{95}{5}=19

So, the original price for one lunch special is $19.

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Answer:

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Step-by-step explanation:

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Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,46)".And we see that t_{\alpha/2}=2.01  

Now we have everything in order to replace into formula (1):  

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Part b

The margin of error is given by this formula:  

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And on this case we have that ME =7 msec, we are interested in order to find the value of n, if we solve n from equation (1) we got:  

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