The original price for one lunch special is $19.
<em><u>Explanation</u></em>
The original price for one lunch special is 'p' dollar.
He wins a coupon for $4 off for each of five days. That means , <u>he needs to pay dollar each day</u>.
So, the total amount needed to pay for 5 days dollar
Given that, <u>he pays $75 for his 5 lunch specials</u>. So the equation will be.....
So, the original price for one lunch special is $19.
Answer:
g(x) = (1/6)(x +7)^2 -8
Step-by-step explanation:
The transformation ...
g(x) = a·f(x -h) +k
represents vertical scaling by a factor of 'a', right shift by h units, and up shift by k units. You want the function g(x) for f(x) = x^2, a = 1/6, h = -7, and k = -8. Those transformations give you ...
g(x) = (1/6)(x +7)^2 -8
