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3 years ago

A number decreased by three square

Mathematics

1 answer:

Leto [7]3 years ago

8 0

A number decreased by three square is: (where x is the number)

x - 3^2

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Millie works 8 hours on Saturday and earns £6.50 an hour. She spends £2.75 on bus fares travelling to work and £4.25 on her lunc

Fudgin [204]

I think it is 42 because 2.75 + 4.25 is 7 x 6= 42

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3 years ago

Find the sum of the arithmetic sequence 1,3,5,7, .. , 99.

Yakvenalex [24]

Answer:

Look at picture answer is 2500

Step-by-step explanation:

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2 years ago

F(x) = 3x + 2

Vinvika [58]

Answer:

g(f(x)) = 9x² + 12x + 5

Step-by-step explanation:

g(f(x))

= g(3x + 2) ← substitute x = 3x + 2 into g(x)

= (3x + 2)² + 1

to expand (3x + 2)² = (3x + 2)(3x + 2)

each term in the second factor is multiplied by each term in the first factor

3x(3x + 2) + 2(3x + 2) ← distribute both parenthesis

= 9x² + 6x + 6x + 4 ← collect like terms

= 9x² + 12x + 4

then

g(f(x)) = (3x + 2)² + 1 = 9x² + 12x + 4 + 1 = 9x² + 12x + 5

5 0

1 year ago

Please show me how to do this.

Aloiza [94]

Answer:

$f(x) = \dfrac{1}{2}(x - \ln (x - 1) - 2)$

Step-by-step explanation:

$f'(x) = \dfrac{1}{2} - \dfrac{1}{2x - 2}$

$f(x) = \int (\dfrac{1}{2} - \dfrac{1}{2x - 2}) dx$

$f(x) = \int [\dfrac{1}{2} - \dfrac{1}{2(x - 2)}] dx$

$f(x) = \int \dfrac{1}{2}dx - \dfrac{1}{2} \int \dfrac{1}{x - 1} dx$

$f(x) = \dfrac{1}{2}x - \dfrac{1}{2} \ln (x - 1) + C$

$f(x) = \dfrac{x - \ln (x - 1)}{2} + C$

$f(2) = \dfrac{2 - \ln (2 - 1)}{2} + C = 0$

$f(2) = \dfrac{2 - \ln (1)}{2} + C = 0$

$f(2) = \dfrac{2}{2} + C = 0$

$f(2) = 1 + C = 0$

$C = -1$

$f(x) = \dfrac{x - \ln (x - 1)}{2} - 1$

$f(x) = \dfrac{1}{2}[x - \ln (x - 1) - 2]$

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3 years ago

Use the picture below to answer the following...Write the ratio of stars to all shapes in all 3 forms (remember to simplify).

deff fn [24]

Answer: 6 to 3 6:3 6/3

Step-by-step explanation:

6 0

2 years ago