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3 years ago

Find the value of x.(tangent)

Mathematics

2 answers:

mariarad [96]3 years ago

8 0

Answer:

5 $\sqrt{2}$

Step-by-step explanation:

Special triangle. 1:1: $\sqrt{2}$

yan [13]3 years ago

4 0

Step-by-step explanation:

Here

With reference angle 45°

hypotenuse (h) =x

perpendicular (p) = 5

Let

Sin45° = p/h

1/√2 = 5/ x

therefore x = 5√2

Now

b=?

Using Pythagoras theorem

b² = h² -p²

b² = (5√2)² - 5²

b² = 50 - 25

b² = 25

b² = 5²

Therefore b = 5

Now

tangent = p/b = 5/5 = 1

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3 years ago

What is the biggest possible answer you can get by putting

Arte-miy333 [17]

Answer:

9-4+(5x3)

Step-by-step explanation:

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3 years ago

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mafiozo [28]

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2 years ago

a parking meter accepts only 20p coins or 50p coins.On one day, 39 coins were collected with a total value of $11.40. find how m

Snowcat [4.5K]

Answer:

x + Y = 39 or x = 39-y

20x + 50y = 1.40

20 (39 - y) + 50y = 11.40

7.80 - 20y + 50y = 11.40

30y = 11.40 - 7.80

30y = 3.60

y = 3.60/30

y = 12 50p coins were collected.

x = 39 - 12 = 27 20p coins were collected.

Proof:

20*27 + 50*12 = 11.40

5.40 + 6 = 11.40

11.40 = 11.40

I hope it helps.

6 0

2 years ago

Read 2 more answers

In order to remove water from a flooded basement, two pumps, each rated at 40 gallons per minute, are used. After half an hour,

Scrat [10]

Answer:

3600 gallons of water was removed from the basement.

Step-by-step explanation:

Given:

Rate of each pump = 40 gallons/min

We need to find find the number of gallons of water removed from the basement.

Solution:

Now Given:

After half an hour, the one pump burns out.

Now we know that;

1 hour = 60 mins

$\frac12$ hour = $\frac{60}{2}=30\ mins$

Now for 30 mins both the pumps were working and removing the water.

So we can say that;

Water remove for first 30 mins = $40\times2\times30=2400\ gallons$

Also Given:

the second pump finishes removing the water half an hour later.

So we can say that;

Water removed for next 30 mins = $40\times 30\times1 =1200\ gallons$

Now we can say that;

Total water removed from the basement is equal to sum of Water remove for first 30 mins and Water removed for next 30 mins .

framing in equation form we get;

Total water removed from the basement = $2400+1200=3600\ gallons.$

Hence 3600 gallons of water was removed from the basement.

6 0

3 years ago

Find the value of x.(tangent)​

Find the value of x.(tangent)