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goblinko [34]
3 years ago
7

6⋅7-3^2⋅9+4^3 what is the value?

Mathematics
2 answers:
Lostsunrise [7]3 years ago
8 0

Answer:

-10

Step-by-step explanation:

First, evaluate the terms with exponents.

7-3²·9+4³

With that, you get:

7-9·9+64

Multiply -9×9

7-81+64

Then, add or substract from left to right.

Your final answer is -10.

zalisa [80]3 years ago
4 0

\textsf{Hey there!}

\mathsf{Equation: 6 \times 7- 3^2 \times9+4^3}

\mathsf{3^2 = 3\times3=9}

\mathsf{4^3= 4\times4\times4=16\times4 = 64}

\mathsf{6\times7 = 42}

\mathsf{9\times9= 81}

\mathsf{New\ equation: 42 - 81 + 64}

\mathsf{42 -81= -39}

\textsf{New equation: -39 + 64}

\mathsf{SOLVE\ ABOVE\ \uparrow\ \& you\ will\ have\ your\ answer\ to\ this\ problem}

\mathsf{-39 + 64 = 25}

\boxed{\textsf{Thus, your answer is: \boxed{\mathsf{\bf{25}}}}}\checkmark

\textsf{Good luck on your assignment and enjoy day!}

~\frak{LoveYourselfFirst:)}

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6 0
3 years ago
The Surface Area of a square pyramid is 3600 ft. The slant height is 80 feet and the base is 20 feet. At most how many 1 foot cu
amm1812

Answer:

10,583 flexible cubes

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Step-by-step explanation:

The equation for the surface area of a square pyramid is area of base plus perimeter of base multiplied by the slant height

Surface area = A + 1/2·p·s

The volume of the pyramid = 1/3×A×h

Where:

A = Area of the base = 20 × 20 = 400 ft²

h = The height of the pyramid = √((slant height)² - ((base side length)/2)²)

h = √(80² - (20/2)²) = 30·√7

The volume of the pyramid = 1/3*400*30·√7 = 4000·√7 ft³ = 10,583.005 ft³

If the cubes are flexible, approximately 10,583 cubes

For rigid cubes we have

Given that the height of the pyramid = 30·√7

The slope of the pyramid = 30·√7/10 = 3·√7

So an increase in height of 1 foot gives a reduction in width of 2/(3·√7)

The bottom can hold 400 cubes

The next layer can hold 19×19 = 361

3rd 361

4th 361

5th 324

6th 324

7th 324

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9th

Continuing, we get a total of about 9915 rigid cubes in the pyramid.

3 0
3 years ago
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Answer:

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Step-by-step explanation:

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