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dimaraw [331]
3 years ago
15

An item on sale costs 25% of the original price. If the original price was $20 , what is the sale price?

Mathematics
2 answers:
nikklg [1K]3 years ago
4 0
20x25%=5

the sale price is $5
Lorico [155]3 years ago
3 0
So an additional discount of 50% off the sale price would bringthe price to 35% (that is, 50% • 70%) of the original price. Thus, a $100item would cost $35 after both discounts. An 80% off sale means thatyou pay 100% – 80%, or 20% of the original cost of the item.
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A)


\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
Q&({{ 0}}\quad ,&{{ 2}})\quad 
%  (c,d)
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\end{array}\qquad 
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d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}

\bf QP=\sqrt{(0.5-0)^2+(0-2)^2}\implies QP=\sqrt{0.5^2+2^2}
\\\\\\
QP=\sqrt{\left( \frac{1}{2} \right)^2+4}\implies QP=\sqrt{ \frac{1^2}{2^2}+4}\implies QP=\sqrt{\frac{1}{4}+4}
\\\\\\
QP=\sqrt{\frac{17}{4}}\implies QP=\cfrac{\sqrt{17}}{\sqrt{4}}\implies QP=\cfrac{\sqrt{17}}{2}

b)

since QR=QP, that means that QO is an angle bisector, and thus the segments it makes at the bottom of RO and OP, are also equal, thus RO=OP

thus, since the point P is 0.5 units away from the 0, point R is also 0.5 units away from 0 as well, however, is on the negative side, thus R (-0.5, 0)


c)

what's the equation of a line that passes through the points (-0.5, 0) and (0,2)?

\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%   (a,b)
Q&({{ 0}}\quad ,&{{ 2}})\quad 
%   (c,d)
R&({{ -0.5}}\quad ,&{{ 0}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{0-2}{-0.5-0}\implies \cfrac{-2}{-0.5}

\bf m=\cfrac{\frac{-2}{1}}{-\frac{1}{2}}\implies \cfrac{-2}{1}\cdot \cfrac{2}{-1}\implies 4
\\\\\\
% point-slope intercept
y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-2=4(x-0)\implies y=4x+2\\
\left. \qquad   \right. \uparrow\\
\textit{point-slope form}
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natali 33 [55]

Step-by-step explanation:

well, the starting equation and the target format have been given.

let's do the multiplications and compare the target with the starting information.

from there we see what is different or missing.

x² + 14x + 13 = 0

and

(x - p)² = q

x² - 2px + p² = q

x² - 2px + (p² - q) = 0

now let's compare the different parts :

x² = x²

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so, the square (x - p)² = (x + 7)² is completed when

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but we have only "+ 13". so we need to add 36 to get 49. but we need to do it on both sides, to keep the equation true :

x² + 14x + 13 + 36 = 36

x² + 14x + 49 = 36

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just as we calculated already above.

and now this can be solved by pulling the square root on both sides (a quadratic equation has always 2 solutions)

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