This is an incomplete question, here is a complete question.
A reaction at 12.0 °C evolves 358 mmol of sulfur tetrafluoride gas. Calculate the volume of sulfur tetrafluoride gas that is collected. You can assume the pressure in the room is exactly 1 atm. Round your answer to 3 significant digits.
Answer : The volume of sulfur tetrafluoride gas collected is, 8.38 L
Explanation :
Using ideal gas equation :
![PV=nRT](https://tex.z-dn.net/?f=PV%3DnRT)
where,
P = Pressure of gas = 1 atm
V = Volume of gas = ?
n = number of moles of gas = 358 mmol = 0.358 mol (1 mmol = 0.001 mol)
R = Gas constant = ![0.0821L.atm/mol.K](https://tex.z-dn.net/?f=0.0821L.atm%2Fmol.K)
T = Temperature of gas = ![12.0^oC=273+12.0=285K](https://tex.z-dn.net/?f=12.0%5EoC%3D273%2B12.0%3D285K)
Putting values in above equation, we get:
![1atm\times V=0.358mole\times (0.0821L.atm/mol.K)\times 285K](https://tex.z-dn.net/?f=1atm%5Ctimes%20V%3D0.358mole%5Ctimes%20%280.0821L.atm%2Fmol.K%29%5Ctimes%20285K)
![V=8.38L](https://tex.z-dn.net/?f=V%3D8.38L)
Thus, the volume of sulfur tetrafluoride gas collected is, 8.38 L