Answer:
NH3(aq)
Explanation:
Gold III hydroxide is an inorganic compound also known as auric acid. It can be dehydrated at about 140°C to yield gold III oxide. Gold III hydroxide is found to form precipitates in alkaline solutions hence it is not soluble in calcium hydroxide.
However, gold III hydroxide forms an inorganic complex with ammonia which makes the insoluble gold III hydroxide to dissolve in ammonia solution. The equation of this complex formation is shown below;
Au(OH)3(s) + 4 NH3(aq) -------> [Au(NH3)4]^3+(aq) + 3OH^-(aq)
Hence the formation of a tetra amine complex of gold III will lead to the dissolution of gold III hydroxide solid in aqueous ammonia.
Answer: 60.1K
Explanation:
Initial volume of gas V1 = 423.3mL
Initial temperature T1 = 49.2°C
Convert temperature in Celsius to Kelvin
( 49.2°C + 273 = 322.2K)
Final temperature T2 = ?
Final volume V2 = 79mL
According to Charle's law, the volume of a fixed mass of a gas is directly proportional to the temperature.
Mathematically, Charles' Law is expressed as: V1/T1 = V2/T2
423.3mL/322.2 = 79mL/T2
To get the value of T2, cross multiply
423.3mL x T2 = 322.2K x 79mL
423.3mL x T2 = 25453.8
T2 = (25453.8/423.3mL)
T2 = 60.1K
Thus, the new temperature of the gas is 60.1K
Answer:
the cell enentually dies because it has no way to survive
Explanation:
Answer:
A chemical change because a temperature change occurred, the solid disappeared and a gas was produces
Explanation:
Magnesium reacts with hydrochloric acid releasing energy, and leading to the formation of magnesium chloride and hydrogen gas. This is represented by the equation below:
Mg₍s₎ + 2HCl₍aq)⇒ MgCl₂₍aq₎ + H₂₍g₎
