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3 years ago

Describe how iodine can tell you if there is starch in a substance?

1 answer:

4 0

Iodine reacts to amylose. Amylose is a polychloride found in starches when combined with iodine the substance then becomes blue. This is because the iodine is becoming iodide.

Hope this helps!

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(b) What amount (mol) of H₂ can be produced from the given mass of H₂O?

Luden [163]

8 moles of H 2O are produced.

First, we need to figure out the chemical equation for producing water with oxygen which is H 2 + O2 = H 2O. Then, we need to balance the equation, resulting in 2H 2 + O2 = 2H 2O.

<h3>How many moles of H2 are required to make one mole of NH3?</h3>

Calculate 0.88074 mol H2's mass. If N2 is too much, 1.776 g H2 is needed to create 10.00 g of NH3. To create 8.2 moles of ammonia, 2 moles of NH3 are created when 1 mole of N2 and 3 moles of H2 mix. 4.1 moles of N2 Fast are consequently needed to make 8.2 moles of NH3.

<h3>How many moles of h2 are needed to produce a solution?</h3>

An O-H bond has a bond energy of 1 09 Kcal. 3.6. A 38.0mL 0.026M HCl solution and a 0.032M NaOH solution react. Thus, 10 moles of NH 3 are obtained by dividing 15 moles of H2 by the 1.5 moles of H2 required for the product. and 9.3 x 10-3 moles of bromobutane (1.27/137 =.00927moles).

Learn more about H2O:

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8 0

2 years ago

50 ml of 0.2 M acetic acid is shaken with 10 g activated charcoal. The concentration of acetic acid is reduced to 0.5 times the

Olegator [25]

Answer:

$0.03 g_{acid}/g_{charcoal}$

Explanation:

The amount adsorbed (solute) is the acetic acid, and the adsorbent is the activated charcoal. The mass of the adsorbent is 10 g.

So, we need to calculate the mass of the acetic acid as follows:

$m = n*M = C*V*M$

Where:

n: is the number of moles = C*V

M: is the molecular mass = 60.052 g/mol

C: is the final concentration of the acid = 0.5*0.2 mol/L = 0.10 mol/L

V: is the volume = 50 ml = 0.050 L

$m_{acid} = C*V*M = 0.10 mol/L*0.050 L*60.052 g/mol = 0.30 g$

Now, the amount of solute adsorbed per gram of the adsorbent is:

$\frac{m_{acid}}{m_{charcoal}} = \frac{0.30 g}{10 g} = 0.03 g_{acid}/g_{charcoal}$

Therefore, the amount of solute adsorbed per gram of the adsorbent is 0.03 g/g.

I hope it helps you!

3 0

2 years ago

Some of Earth layers are not solid and are able to flow true or false

aalyn [17]

Answer:

True?

can I have brainiest pls

≡(▔﹏▔)≡

7 0

3 years ago

Automobile airbags contain solid sodium azide, nan3, that reacts to produce nitrogen gas when heated, thus inflating the bag.

forsale [732]

The values of work, w, for the system if 16.5 g NaN 3 reacts completely at 1.00 atm and 22 ∘ C. The work done is -919 J.

The equation of the reaction is;

2 NaN 3 ( s ) ⟶ 2 Na ( s ) + 3 N 2 ( g )

Number of moles of NaN3 = 16.5 g/65 g/mol = 0.25 moles

If 2 moles of NaNa3 yields 3 moles of N2

0.25 moles of NaN3 yields 0.25 moles × 3 moles/2 moles

= 0.375 moles of N2

We need to find the volume change using the;

PV = nRT

P = 1.00 atm

V =?

n = 0.375 moles of N2

R = 0.082 atmLK-1mol-1

T = 22 ∘ C + 273 = 295 K

V = nRT/P

V = 0.375 × 0.082 × 295/ 1.00

V = 9.07 L

Recall that during expansion the gas does work. Work done by the gas is;

W = -PΔV

W =-( 1 atm × 9.07 L)

W = -9 Atm

Again;

1 L atm = 101.325 J

So,

-9 atmL = -9 atmL × 101.325 J/1 L atm

= -919 J

The work done is -919 J.

Learn more about work done here:-brainly.com/question/25573309

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<u>Disclaimer:- your question is incomplete, please see below for the complete question.</u>

Automobile airbags contain solid sodium azide, NaN 3, that reacts to produce nitrogen gas when heated, thus inflating the bag. 2 NaN 3 ( s ) ⟶ 2 Na ( s ) + 3 N 2 ( g ) Calculate the value of work, w, for the system if 16.5 g NaN 3 reacts completely at 1.00 atm and 22 ∘ C.

5 0

1 year ago

What kind of acid is produced by our muscles when we exercise?

tatuchka [14]

The answer is sweat i believe

3 0

3 years ago

Read 2 more answers