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adelina 88 [10]
4 years ago
5

If in the following diagram the substance is in the solid state during stage 1, what is happening during stage 2?

Chemistry
2 answers:
a_sh-v [17]4 years ago
8 0

Answer:

Here is the diagram.

Explanation:

Iteru [2.4K]4 years ago
3 0
If in the following diagram the substance is in the solid state during stage 1,  during stage 2 the substance is boiling or condensing .
Boiling<span> is the term used to describe the rapid vaporization of a liquid. Boiling occurs when a liquid is heated to its </span>boiling<span> point. 
</span>Condensation happens when the gas is changed into liquid. 
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A 25.0-mL sample of 0.100M Ba(OH)2(aq) is titrated with 0.125 M HCl(aq).
morpeh [17]

Answer:

20.0

Explanation:

NaOH = (25.0) (0.100m) \ 0.125M = 20.0mL

8 0
3 years ago
The structural form of the element Ge closely resembles the structure of A. C (diamond) B. N (diatomic) C. As (tetrahedral) D. S
Ksivusya [100]

The structural form of the element Ge closely resembles the structure of C (diamond).

Diamond is composed of a lattice structure in which atoms of carbon are held together in a face centered cubic lattice.

Germanium, an element in the same group as carbon also forms a face centered cubic lattice that is very similar to that of diamond.

Hence, the  structural form of the element Ge closely resembles the structure of C (diamond).

Learn more: brainly.com/question/14578576

6 0
3 years ago
8. A 220 mL sample of helium gas is in a cylinder with a movable piston at 105 kPa and 275K. The piston
Harrizon [31]

The sample has a new pressure of 274kPa. If at 105 kPa and 275K, a 220 mL sample of helium gas is contained in a cylinder with a moving piston. The sample is pushed till it has a 95.0 mL volume and 310K .

The macroscopic characteristics of ideal gases are related by the ideal gas law (PV = nRT). A gas is considered to be perfect if its particles (a) do not interact with one another and (b) occupy no space (have no volume). Where P= pressure  V= volume and T = temperature.

From ideal gas equation

P₁V₁/T₁ =P₂V₂/T₂

105×220÷275 = P₂ ×95÷310

P₂= (105×220×310)÷(275×95)

P2= 7161000/26125

P2 = 274.105 kPa

Hence, the new pressure of helium gas is 274kPa

To know more about Ideas gas equation

brainly.com/question/28837405

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8 0
1 year ago
For a principal quantum number n, how many atomic orbitals are possible?
slavikrds [6]

Answer:

The total number of orbitals for a given n value is n2.

Explanation:

For a hydrogen atom with n=1, the electron is in its ground state; if the electron is in the n=2 orbital, it is in an excited state.

5 0
3 years ago
......................................................
Diano4ka-milaya [45]

Answer:

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5 0
3 years ago
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