1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
iren [92.7K]
3 years ago
14

I will give brainliest and 76 points

Chemistry
1 answer:
katen-ka-za [31]3 years ago
8 0

Answer:

number 5 is the answer

Explanation:

You might be interested in
What is the theoretical yield of vanadium, in moles, that can be produced by the reaction of 1.0 mole of V2O5 with 4.0 moles of
IRINA_888 [86]

Answer:

Theoretical yield of vanadium = 1.6 moles

Explanation:

Moles of V_2O_5 = 1.0 moles

Moles of Ca = 4.0 moles

According to the given reaction:-

V_2O_5_{(s)} + 5Ca_{(l)}\rightarrow 2V_{(l)} + 5CaO_{(s)}

1 mole of V_2O_5 react with 5 moles of Ca

Moles of Ca available = 4.0 moles

Limiting reagent is the one which is present in small amount. Thus, Ca is limiting reagent. (4.0 < 5)

The formation of the product is governed by the limiting reagent. So,

5 moles of Ca on reaction forms 2 moles of V

1 mole of Ca on reaction for 2/5 mole of V

4.0 mole of Ca on reaction for \frac{2}{5}\times 4 mole of V

Moles of V = 1.6 moles

<u>Theoretical yield of vanadium = 1.6 moles</u>

4 0
3 years ago
Is helium a homogeneous or heterogeneous mixture or compound or element?
sattari [20]
Helium is a chemical ELEMENT of the family of noble gases. Its chemical symbol is 'He' which has an atomic number of 2. It is a colorless, odorless, tasteless, non-toxic, inert, monatomic gas, the first in the noble gas group in the periodic table. Although it doesn't really react under normal conditions, it is the second most abundant element in the universe.

Elements are pure substances that cannot be broken down any further.
8 0
3 years ago
3. What is the substance ozone?
Reptile [31]
Chlorofluorocarbons and other halogenated ozone depleting substances are mainly responsible for man made chemical ozone depletion.
8 0
3 years ago
starting with methane ,name all the steps and write the equations involved in tetrachlorination.Remember all arrows sharing move
anygoal [31]

Answer:

See Explanation and image attached

Explanation:

Methane is an alkane. The commonest chemical reaction that alkanes undergo is substitution. During a substitution reaction, one or more atoms of hydrogen is/are replaced in the alkane.

In methane, in the presence of sunlight and molecular chlorine gas, a homolytic fission of Cl2 occurs to yield chlorine radicals in an initiation step.

The propagation steps involve reaction of the methane with chlorine radicals. Certain intermediates continue to be formed along the way until the tetrachlorination product is finally obtained.

4 0
3 years ago
How would this atomic structure change if you built an atom of Krypton which has an atomic number of 36?
jenyasd209 [6]

Answer:

Explanation:

d

5 0
3 years ago
Other questions:
  • How many particles are contained in 2.75 moles of aluminum fluoride?
    11·1 answer
  • Calculate the mass of arsenic(III) chloride produced when 0.150 g of arsenic reacts with excess chlorine according to the equati
    6·1 answer
  • What is Mendeleev most known for?
    8·1 answer
  • Why Is It Important To Classify The Millions Of Species On Earth
    7·2 answers
  • Does a fish's scales shred as the fish grows larger
    7·1 answer
  • TRUE OR FALSE? Alloys are used more than pure metals because they are generally softer and less likely to react with air or wate
    8·1 answer
  • Consider the energy diagram below.
    8·1 answer
  • Why do you think neutrons are necessary in the nucleus of an atom?
    14·2 answers
  • The table shows the boiling points of fluorine, chlorine and bromine.
    5·2 answers
  • According to the beer-lambert law, what happens to the absorbance value of a light-absorbing chemical when its concentration inc
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!