We have that
x² − 8xy + y²<span> = 8
</span>2x-8y-8x(dy/dx)+2y*(<span>dy/dx)=0
</span>8x(dy/dx)-2y*(dy/dx)=2x-8y
[8x-2y]*(dy/dx)=2x-8y
(dy/dx)=[2x-8y]/[8x-2y]
(dy/dx)=2*[x-4y]/2*[4x-y]
(dy/dx)=[x-4y]/[4x-y]
the answer is
(dy/dx)=[x-4y]/[4x-y]
The answer is 12/5 or 2.4
Answer: Bridge is 21 years old
Step-by-step explanation:
Ok so after reading the question I already know that B (Bridget), A (Angad) and P (Paul) is 49 in the sum of age. I also know that B=A+5 and P=A-4. After that I can assume B=P+5+4. So now after we gather everything, the age of all of them is the same if we delete 5, 4, 4 (From B=P+5+4 and P=A-4). 49-5-4-4=36. So now lets assume they are all 12 (36/3=12). B is 5 years older so lets add 5 to B. B=17, A=12 and P=8. 8+12+17= 37. We now know that but 37 is 12 under 49, so lets add the average 12/3=4 so we add 4 to all of them. B=21 A=16 P=12. 21+16+12=49. So Bridge is 21 years old, Angad is 16 years old and Paul is 12 years old
Answer: $3000
Step-by-step explanation:
$5000 x .03 = $150
$150 x 4(quarters) = $600
$600 x 5(years) = $3000
