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Rina8888 [55]
3 years ago
10

Will vote

Mathematics
1 answer:
tia_tia [17]3 years ago
6 0
The answer is 1 to 3
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She has 12 necklaces in 2 hours. How long will it take her to make 9 necklaces
natulia [17]
12/2 = 6 per hour

6/2 = 3 in 30 minutes.

6+3 = 9

6= 1 hour
3 = 30 minutes.

ADD 1 HOUR + 30 MINUTES = 1 HOUR AND 30 MINUTES.

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Which of the following is not required by lenders and investors?
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Please answer!!! I’ll make brainliest
gizmo_the_mogwai [7]

Answer: 30

Step-by-step explanation:

1. Use the Pythagorean theorem (A^{2} +B^{2} = C^{2})

 

18^{2} +24^{2} =C^{2} \\324 + 576 = C^{2} \\900 = C^{2} \\\sqrt{900} = \sqrt{C^{2} } \\30 = C\\

8 0
3 years ago
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If the difference of two numbers is 43 in the sum of the numbers is 13 what are the numbers
bulgar [2K]
A-b = 43----(1)
a+b = 13----(2)

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4 0
3 years ago
A total of 937 people attended the play admission was $2.00 for adults and $0.75 for students. The total ticket sales amounted t
mamaluj [8]

612 students attended and 325 adults attended the play

<h3><u>Solution:</u></h3>

Let "s" be the number of students attended the play

Let "a" be the number of adults attended the play

Cost of 1 adult ticket = $ 2

Cost of 1 student ticket = $ 0.75

<em><u>Given that total 937 people attended the play</u></em>

number of students + number of adults = 937

s + a = 937 ---------- eqn 1

<em><u>The total ticket sales amounted to $1,109</u></em>

number of adults x Cost of 1 adult ticket + number of students x Cost of 1 student ticket = 1109

a \times 2 + s \times 0.75 = 1109

2a + 0.75s = 1109 ---- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

From eqn 1,

s = 937 - a -------- eqn 3

<em><u>Substitute eqn 3 in eqn 2</u></em>

2a + 0.75(937 - a) = 1109

2a + 702.75 - 0.75a = 1109

1.25a = 1109 - 702.75

1.25a = 406.25

a = \frac{406.25}{1.25}

<h3>a = 325</h3>

From eqn 3,

s = 937 - 325

<h3>s = 612</h3>

Thus 612 students attended and 325 adults attended the play

3 0
3 years ago
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