Consider the molar solubility of SrCO3 in 0.10 M Sr(NO3)2 versus in pure water. Ksp SrCO3 = 5.4 x 10-10 Which statement is true?
1 answer:
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Answer:
11.905 km/L
Explanation:
Given that,
A car gets 28.0 miles/gallon of gas on the highway.
We need to find the volume into km/L
We know that,
1 mile = 1.60934 km
Also,
1 gallon = 3.785 litre
So,
Hence, the car get 11.905 km/L of the gas.
Answer:
The molar mass of the gas is 36.25 g/mol.
Explanation:
- To solve this problem, we can use the mathematical relation:
ν =
Where, ν is the speed of light in a gas <em>(ν = 449 m/s)</em>,
R is the universal gas constant <em>(R = 8.314 J/mol.K)</em>,
T is the temperature of the gas in Kelvin <em>(T = 20 °C + 273 = 293 K)</em>,
M is the molar mass of the gas in <em>(Kg/mol)</em>.
ν =
(449 m/s) = √ (3(8.314 J/mol.K) (293 K) / M,
<em>by squaring the two sides:</em>
(449 m/s)² = (3 (8.314 J/mol.K) (293 K)) / M,
∴ M = (3 (8.314 J/mol.K) (293 K) / (449 m/s)² = 7308.006 / 201601 = 0.03625 Kg/mol.
<em>∴ The molar mass of the gas is 36.25 g/mol.</em>