SN1 is a substitution reaction
with n being the nucleophilic substitution an 1 represents a unimolecular
reaction. Because the given molecule on the central carbon is sterically
hindered, the rate of carbocation formation is increased dramatically. It will
make the OT (leaving group) to leave and a nucleophile (nucleophilic attack) will
react to the carbocation.
Answer:

Explanation:
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In this case, since pyridinium chloride has a pKb of 8.77 which is a Kb of 1.70x10⁻⁹ and therefore a Ka of 5.89x10⁻⁵ which means it tends to be acidic, we write its ionization via:

Because it is a Bronsted base which donates one hydrogen ion to the water to produce hydronium. Thus, we write the equilibrium expression with the aqueous species only:
![Ka=\frac{[C_5H_5NCl^-][H_3O^+]}{[C_5H_5NHCl]}](https://tex.z-dn.net/?f=Ka%3D%5Cfrac%7B%5BC_5H_5NCl%5E-%5D%5BH_3O%5E%2B%5D%7D%7B%5BC_5H_5NHCl%5D%7D)
In terms of the reaction extent
, we write:

Thus, solving for
we obtain:

Clearly the solution is 0.0048 M because to negative values are not allowed, therefore, since it equals the concentration of hydronium which defines the pH, we write:
![pH=-log([H_3O^+])=-log(0.0048)\\\\pH=2.3](https://tex.z-dn.net/?f=pH%3D-log%28%5BH_3O%5E%2B%5D%29%3D-log%280.0048%29%5C%5C%5C%5CpH%3D2.3)
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The atomic mass of Aluminum is around 27 amu. There are two aluminum atoms, so it takes 54 amu. The gram-formula states that 1 mole of this compound has 342 grams. By definition, this means that the total amu of this compound is 342. Therefore, we divide 54 by 342 to get around 15.8 %.
Neon is an element because it is a pure atom