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puteri [66]
3 years ago
6

Anyone know how to solve this?

Mathematics
1 answer:
vampirchik [111]3 years ago
6 0

Answer:

10

Step-by-step explanation:

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Please assist with this question!!!!!!!!!! No links or your account will be banned
andriy [413]

Answer:

8/15

Step-by-step explanation:

4 0
2 years ago
To conduct an experiment, researches randomly select six students from a class of 20. How many different groups of six students
enot [183]

Answer:

3.33

Step-by-step explanation:

20 divided by 6 equals 3.33333333333

Round that you get 3.33

8 0
3 years ago
Find the measure of the numbered angle.
Mila [183]
The angle adjacent to angle 6 is the one we need to find first.  To do this, add the measures of the intercepted arcs and divide by 2.  60 + 50 = 110, and half of that is 55.  That means that both adjacent angles to the angle 6 are 55 (vertical angles are congruent).  The measure of all the angles added together is 360 and angle 6 is vertical to the other "sideways" angle, so they are congruent as well.  360 - 55 - 55 = 250.  Split that up between angle 6 and its vertical angle to get that each of those measure 125.  Angle 6 measures 125, choice b from above.
4 0
3 years ago
Prove that the triangle EDF is isosceles. Give reasons for your answer.
Gekata [30.6K]

Answer:

\triangle EDF is isosceles.

Step-by-step explanation:

Please have a look at the attached figure.

We are <u>given</u> the following things:

\angle EDF = y

\text{External }\angle DFG = 90 +\dfrac{y}{2}

Let us try to find out \angle E and \angle DFE. After that we will compare them.

<u>Finding </u>\angle DFE<u>:</u>

Side EG is a straight line so \angle GFE = 180

\angle GFE is sum of internal \angle DFE and external \angle DFG

\angle GFE = 180 = \angle DFE  + \angle DFG\\\Rightarrow 180 = \angle DFE + (90+\dfrac{y}{2})\\\Rightarrow \angle DFE = 180 - 90 - \dfrac{y}{2}\\\Rightarrow \angle DFE = 90 - \dfrac{y}{2} ....... (1)

<u>Finding </u>\angle E<u>:</u>

<u>Property of external angle:</u> External angle in a triangle is equal to the sum of two opposite internal angles of a triangle.

i.e. external \angle DFG = \angle E + \angle EDF

\Rightarrow 90+\dfrac{y}{2} = \angle E + y\\\Rightarrow \angle E = 90+\dfrac{y}{2}  -y\\\Rightarrow \angle E = 90-\dfrac{y}{2} ....... (2)

Comparing equations (1) and (2):

It can be clearly seen that:

\angle DFE = \angle E =90-\dfrac{y}{2}

The two angles of \triangle EDF are equal hence \triangle EDF is isosceles.

8 0
3 years ago
The weekly cost (c) of manufacturing (x) number of remotes is given by the equation below. what is the cost to manufacture 2500
IRISSAK [1]
C= 2000 + 3(2500)
C= 2000 + 7,500
C= $9,500
6 0
3 years ago
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