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sweet-ann [11.9K]
3 years ago
8

Simplify:(4x2 - 2x) - (-5x2 - 8x)

Mathematics
2 answers:
Marysya12 [62]3 years ago
7 0

Answer:

4x2+5x2-2x+8x=9x2+6x

Step-by-step explanation:

trapecia [35]3 years ago
6 0

Answer:

24x

Step-by-step explanation:

Calculate the product

8 and 10

(8x-2x)-(-10x-8x)

Collect like terms

(6x)-(-18x)

Remove any unnecessary parentheses

6x-(-18x)

When there is a - in front of an expression in parentheses, change the sign of each term in the expression

6x+18x

Collect like terms

24x

Answer = 24x

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Help me please!!<br> Find x
Galina-37 [17]

Answer:

x=4

Step-by-step explanation:

Since x+2 is half the size of 3x:

2(x+2)=3x

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How would I get this information into Y=Mx+B
andriy [413]
One question at a time, please.  I will focus on #16 and ignore #18.

slope:  3/4              line passes thru (-8,2)

Write out    y = mx + b.  Subst. 2 for y.  Subst. -8 for x  Subst. (3/4) for m:

2 = (3/4)(-8) + b.  Find b.           2 = -6 + b    =>           b = 8

So your equation is y = (3/4)x + 8.  Please, use (  ) around those fractions!
3 0
3 years ago
(c). It is well known that the rate of flow can be found by measuring the volume of blood that flows past a point in a given tim
aleksklad [387]

(i) Given that

V(R) = \displaystyle \int_0^R 2\pi K(R^2r-r^3) \, dr

when R = 0.30 cm and v = (0.30 - 3.33r²) cm/s (which additionally tells us to take K = 1), then

V(0.30) = \displaystyle \int_0^{0.30} 2\pi \left(0.30-3.33r^2\right)r \, dr \approx \boxed{0.0425}

and this is a volume so it must be reported with units of cm³.

In Mathematica, you can first define the velocity function with

v[r_] := 0.30 - 3.33r^2

and additionally define the volume function with

V[R_] := Integrate[2 Pi v[r] r, {r, 0, R}]

Then get the desired volume by running V[0.30].

(ii) In full, the volume function is

\displaystyle \int_0^R 2\pi K(R^2-r^2)r \, dr

Compute the integral:

V(R) = \displaystyle \int_0^R 2\pi K(R^2-r^2)r \, dr

V(R) = \displaystyle 2\pi K \int_0^R (R^2r-r^3) \, dr

V(R) = \displaystyle 2\pi K \left(\frac12 R^2r^2 - \frac14 r^4\right)\bigg_0^R

V(R) = \displaystyle 2\pi K \left(\frac{R^4}2- \frac{R^4}4\right)

V(R) = \displaystyle \boxed{\frac{\pi KR^4}2}

In M, redefine the velocity function as

v[r_] := k*(R^2 - r^2)

(you can't use capital K because it's reserved for a built-in function)

Then run

Integrate[2 Pi v[r] r, {r, 0, R}]

This may take a little longer to compute than expected because M tries to generate a result to cover all cases (it doesn't automatically know that R is a real number, for instance). You can make it run faster by including the Assumptions option, as with

Integrate[2 Pi v[r] r, {r, 0, R}, Assumptions -> R > 0]

which ensures that R is positive, and moreover a real number.

5 0
3 years ago
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Lemur [1.5K]

Answer:

exponent is 0

Step-by-step explanation:

8 0
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