The major axis of the eclipse is 12 units long
The given parameters can be represented as:


See attachment for illustration
To solve this question, we make use of the following theorem
The distance between a point and the foci sums up to the major axis
This translates to:



9514 1404 393
Answer:
(d) ∅
Step-by-step explanation:
Subtracting y from both sides gives ...
4 = -5
There is no value of y that will make this true. <em>There is no solution to the equation</em>.
The solution set is the null set: ∅.
Note: Consider we need to find the vertices of the triangle A'B'C'
Given:
Triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C'.
Triangle A,B,C with vertices at A(-3, 6), B(2, 9), and C(1, 1).
To find:
The vertices of the triangle A'B'C'.
Solution:
If triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C', then

Using this rule, we get



Therefore, the vertices of A'B'C' are A'(6,3), B'(9,-2) and C'(1,-1).
Answer:
-768a
Step-by-step explanation:
6*-2a = -12a
-12a*64 = -768a
Answer:
Step-by-step explanation: