All categories

3 years ago

Two less than the product of 8 and a number is 8

Mathematics

1 answer:

Eva8 [605]3 years ago

3 0

Answer:

x=1.25

Step-by-step explanation:

Let us replace the number with the variable "x". You will then get this equation:

8x-2=8

Move the -2 to 8 and you would get the equation:

8x=8+2

Simplify:

8x=10

Simplify:

x=10/8

You would then get the answer "x=1.25"

I hope this helps :)

You might be interested in

A random sample of adults were asked whether they prefer reading an e-book over a printed book. The survey resulted in a sample

djyliett [7]

Answer: $(0.10\ ,\ 0.18)$

Step-by-step explanation:

According to the empirical rule, the 95% confidence interval for the true population proportion is given by :-

$(p'-2\sigma_{p'}\ ,\ p'+2\sigma_{p'})$

Given : . The survey resulted in a sample proportion of p′=0.14, with a sampling standard deviation of σp′=0.02, who preferred reading an e-book.

Then, the 95% confidence interval for the true proportion of adults who prefer e-books will be :-

$(0.14-2(0.02)\ ,\ 0.14+2(0.02))\\\\=(0.14-0.04\ ,\ 0.14+0.04)\\\\=(0.10\ ,\ 0.18)$

Hence, the 95% confidence interval for the true proportion of adults who prefer e-books= $(0.10\ ,\ 0.18)$

8 0

3 years ago

Find the volume of a cylinder with height 12 cm and diameter 7 cm.

Svet_ta [14]

3 0

3 years ago

12 tickets sold for every 4 tickets not sold if 704 were not sold how many tickets were sold

horsena [70]

there would be 14 tickets

4 0

3 years ago

The time t required to drive a certain distance varies inversely with the speed r. If it takes 2 hours to drive the distance at

Stolb23 [73]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

A certain virus infects one in every 300 people. A test used to detect the virus in a person is positive 90% of the time when t

garik1379 [7]

Answer:

a) P[A/B] = 0,019 or P[A/B] = 1,9 %

b) P[A- /B-] = 0,9996 or P[A- /B-] = 99,96 %

Step-by-step explanation:

Bayes Theorem :

P[A/B] = P(A) * P[B/A] / P(B)

The branches of events are as follows

Condition 1 real infection 1/300 and not infection 299/300

Then

1.- 1/300 299/300

When the test is done (virus present) 0,9 (+) 0,15 (-)

2.- 299/300

When the test is done ( no virus ) 0,15 (+) 0,85 (-)

Then:

P(A) = event person infected P(B) = person test positive

a) P[A/B] = P(A) * P[B/A] / P(B)

where P(A) = 1/300 = 0,0033 P[B/A] = 0,9

Then P(A) * P[B/A] = 0,0033*0,9 = 0,00297

P(B) is ( 1/300 )*0,9 + (299/300)*0,15

P(B) = 0,0033*0,9 + 0,9966*0,15 ⇒ P(B) = 0,1524

Finally

P[A/B] = 0,00297 /0,1524

P[A/B] = 0,019 or P[A/B] = 1,9 %

b) Following sames steps:

P[A- /B-] = (299/300) * 0,85 / (299/300) * 0,85 + (1/300 * 0,1)

P[A- /B-] = 0,8471 /0,8474

P[A- /B-] = 0,9996 or P[A- /B-] = 99,96 %

6 0

3 years ago